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4 years ago

8

The type of image formed by a concave mirror depends on whether a reflected object is located ________________ the focal point a

nd mirror or beyond the focal point.
Please fill in the blank space with the correct answer!!!1

1 answer:

Inga [223]4 years ago

5 0

The answer to fill in the blank is between.

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the millersburg ferry (m=13000.0 kg loaded) puts its engines in full reverse and stops in 65 seconds. if the speed before brakin

kenny6666 [7]

The braking force is -400 N

Explanation:

We can solve this problem by using the impulse theorem, which states that the impulse applied on the ferry (the product of force and time) is equal to its change in momentum:

$F \Delta t = m(v-u)$

where in this problem, we have:

F is the force applied by the brakes

$\Delta t = 65 s$ is the time interval

m = 13,000 kg is the mass of the ferry

u = 2.0 m/s is the initial velocity

v = 0 is the final velocity

And solving for F, we find the force applied by the brakes:

$F=\frac{m(v-u)}{\Delta t}=\frac{(13000)(0-2.0)}{65}=-400 N$

where the negative sign indicates that the direction is backward.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

4 0

3 years ago

A 6.50 meter high cylinder is filled with alcohol(density =806 kg/m^3). What is the pressure at the bottom of the cylinder?

makvit [3.9K]

Answer:

152642.2

Explanation:

the pressure at the bottom of the cylinder is

P = Po + rho gh

=101300+806(9.8)(6.5)

=152642.2 Pa

3 0

3 years ago

What is the longest bone in your body

dsp73

The longest bone in a human body is the Fumer (thigh bone)

4 0

4 years ago

Read 2 more answers

Older televisions display a picture using a device called a cathode ray tube, where electrons are emitted at high speed and coll

gregori [183]

Answer:

a) t = 3.027 10⁻⁹ s , b) y = 2.25 10⁻² m

Explanation:

We can solve this problem using the kinematic relations

a) as on the x-axis there is no relationship

vₓ = x / t

t = x / vₓ

We reduce the magnitudes to the SI system

x = 5.6 cm (1m / 100 vm) = 0.056 m

we calculate

t = 0.056 / 1.85 10⁷

t = 3.027 10⁻⁹ s

b) the time is the same for the two movements, on the y axis

y = v₀t + ½ a t²

as the beam leaves horizontal there is no initial vertical velocity

y = ½ a t²

let's calculate

y = ½ 5.45 10¹⁵ (3.027 10⁻⁹)²

y = 2.25 10⁻² m

6 0

3 years ago

How does the total momentum of the docked vehicle and station compare to the momentum of each object before the

Xelga [282]

The total momentum before the docking maneuver is and after the docking maneuver is

Explanation:

Linear momentum (generally just called momentum) is defined as mass in motion and is given by the following equation:

Where is the mass of the object and its velocity.

According to the conservation of momentum law:

"If two objects or bodies are in a closed system and both collide, the total momentum of these two objects before the collision will be the same as the total momentum of these same two objects after the collision ".

This means, that although the momentum of each object may change after the collision, the total momentum of the system does not change.

Now, the docking of a space vehicle with the space station is an inelastic collision, which means both objects remain together after the collision.

Hence, the initial momentum is:

Where:

is the mass of the vehicle

is the velocity of th vehicle

is the mass of the space station

is the velocity of the space station

And the final momentum is:

Where:

is the velocity of the vehicle and space station docked

5 0

4 years ago