Let's start by using the mirror equation:

where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:

from which we find q=13.6 cm.
The fact that q is positive means that the image is
real, so it is on the same side of the object, with respect to the mirror.
Then we can also find the size of the image with respect to the original object. The magnification is given by

The negative sign means that the image is
inverted, and the size of the image is 0.36 times the size of the object.
Physical development , Cognitive Development , psychosocial development I think!
Answer:
98.33 %
Explanation:
On an elliptical orbit, angular momentum will be conserved .
Angular momentum = I ω = mvR
So mv₁R₁ = mv₂R₂
= v₁R₁ = v₂R₂
where v₁ is velocity and R₁ radius in low orbit (perigee)and v₂ and R₂ is velocity and radius in high orbit ( apogee ).
Here R₁ = Radius of the earth , R₂ is distance between moon and earth.
R₁ / R₂ = 1/60
v₁ /v₂ = R₂ / R₁ = 60
v₂ / v₁ = 1 / 60
1 - (v₂ / v₁ ) = 1 -( 1 / 60)
(v₁ -v₂)/v₁ = ( 60-1 )/60
(v₁ -v₂)/v₁ x 100 = 5900/60 = 98.33 %