This layer of the Earth is made of solid rock, it is hot and made of peridotite.

A block of mass 0.245 kg is placed on top of a light, vertical spring of force constant 4 975 N/m and pushed downward so that th

FromTheMoon [43]

Answer:

10.99 m

Explanation:

m = mass of the block = 0.245 kg

k = spring constant of the vertical spring = 4975 N/m

x = compression of the spring = 0.103 m

h = height to which the block rise

Using conservation of energy

Potential energy gained by the block = Spring potential energy

mgh = (0.5) k x²

(0.245) (9.8) h = (0.5) (4975) (0.103)²

h = 10.99 m

6 0

3 years ago

How is the earth a cracked hard boiled egg

xz_007 [3.2K]

Answer:

the earth isn't a cracked hard boiled egg, but I'd guess they mean layers. A thin shell/crust and the yolk and whites of the egg represent layers of the earth

Explanation:

6 0

2 years ago

Refer to the diagram. Which answer correctly labels the water between the equator and the North Pole?

Korolek [52]

B.---A. warm water B. thermocline C. cold water

5 0

3 years ago

A wheel of radius 25cm has eight spokes. It is mounted on a fixed axle and is rotating at a constant angular speed w. You shoot

spayn [35]

Explanation:

We will assume that the rim of the wheel is also very thin, like the spokes. The distance s between the spokes along the rim is

$s = \frac{1}{8}C = \frac{1}{8}(2\pi)(0.25\:\text{m}) = 0.196\:\text{m}$

The 20-cm arrow, traveling at 6 m/s, will travel its length in

$t = \dfrac{0.2\:\text{m}}{6\:\text{m/s}} = \dfrac{1}{30}\:\text{s}$

The fastest speed that the wheel can spin without clipping the arrow is

$v = \dfrac{s}{t} = \dfrac{0.196\:\text{m}}{\left(\dfrac{1}{30\:\text{s}}\right)} = 5.9\:\text{m/s}$

The angular velocity $\omega$ of the wheel is given by

$\omega = \dfrac{v}{r} = \dfrac{5.9\:\text{m/s}}{0.25\:\text{m}} = 23.6\:\text{rad/s}$

In terms of rev/s, we can convert the answer above as follows:

$23.6\:\dfrac{\text{rad}}{\text{s}}×\dfrac{1\:\text{rev}}{2\pi\:\text{rad}} = 3.8\:\text{rev/s}$

As you probably noticed, I did the calculations based on the assumption that I'm aiming for the edge of the wheel because this is the part of the wheel where a point travels a longer linear distance compared to ones closer to the axle, thus giving the arrow a better chance to pass through the wheel without getting clipped by the spokes. If you aim closer to the axle, then the wheel needs to spin slower to allow the arrow to get through without hitting the spokes.

3 0

2 years ago

What is the speed of a 50 g rock if its de broglie wavelength is 3.32x10^-34m?

ivann1987 [24]

We can find the momentum of the rock by using De Broglie's relationship:
$p= \frac{h}{\lambda}$
where
p is the momentum
h is the Planck constant
$\lambda$ is the De Broglie's wavelength

By using $\lambda=3.32 \cdot 10^{-34} m$ , we find
$p= \frac{6.6 \cdot 10^{-34} Js}{3.32 \cdot 10^{-34} m}=1.99 kg m/s$

The momentum of the rock is
$p=mv$
where $m=50 g=0.05 kg$ is the mass and v is its velocity. Rearranging the equation, we find the speed of the rock:
$v= \frac{p}{m}= \frac{1.99 kg m/s}{0.05 kg}=39.8 m/s$

7 0

3 years ago