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3 years ago

Please help giving 15 points How do you calculate the density of an object?

Physics

2 answers:

sesenic [268]3 years ago

8 0

Divide the mass over volume d=m/v

Elis [28]3 years ago

3 0

You first find the mass and the volume of that object. Then you divide mass ÷ volume

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a 2.964 kilogram truck strikes a fence at 7.00 meters/second and comes to a stop in 1.9 seconds. what was the average force acti

tangare [24]

10.92N

Explanation:

Given parameters:

Mass of the truck = 2.964kg

velocity = 7m/s

Time = 1.9s

Unknown;

Average force on the car = ?

Solution:

The force acting on the car is a function of its mass and acceleration according the newton's second law of motion.

Force = mass x acceleration

Since acceleration = $\frac{change in velocity}{time}$

Force = mass x $\frac{change in velocity}{time}$

Force = $\frac{2.964 x 7 }{1.9}$

= 10.92N

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

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2 years ago

Where is our solar system located in the Milky Way?

SSSSS [86.1K]

Our solar system is located in the outer reaches of the Milky Way Galaxy, which is a spiral galaxy .

7 0

3 years ago

AP physics Will give brainliest to correct answer.

rjkz [21]

Answer:

the 4th one

Explanation:

6 0

3 years ago

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A 740-kg boulder is raised from a quarry 119 m deep by a long uniform chain having a mass of 550 kg . This chain is of uniform s

Naddika [18.5K]

Answer:

A) the maximum acceleration the boulder can have and still get out of the quarry

B) how long does it take to be lifted out at maximum acceleration if it started from rest

Explanation:

let +y is upward. look below at the free body diagram. the mass M refers to the combined mass of the boulder and chain.

the weight of the chain is: $w_{c} =m_{c} g$ and maximum tension is $T=2.50 m_{c} g=1.41*10^4N$

total mass and weight is :

$M =m_{c}+ m_{b} =740kg+550kg=1290 kg$

$w_{M} =1.2650*10^4N$

∑ $F_{y} =ma_{y}$

$T-M_{g} =Ma_{y}$

$a_{y} =(t-M_{g} )/M=(2.50m_{c} -M_{g} )/M=(2.50.550kg-1290kg)(9.8m/s^2)/1290kg$

$=0.645m/s^2$

maximum acceleration

$a_{y} =0.645m/s^2\\\\y-y_{0} =119m\\v_{0y} =0$

using $y-y_{0} =v_{oy} t+1/2(a_{y} )t^2$

to solve for t

$t=\sqrt{2(y-y_{0} )/a_{y} }$

$t=\sqrt{2(119m)/0.645m/s^2} =19.20s$

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3 years ago

2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is

olga2289 [7]

Answer:

her displacement <em>s=337.5m</em>

Explanation:

check out the above attachment ☝️

7 0

1 year ago

Read 2 more answers