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swat32
4 years ago
6

What are examples of non mechanical energy

Physics
1 answer:
ExtremeBDS [4]4 years ago
3 0

Atoms, molecules, electrons, photons, protons etc.

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An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity c
stiv31 [10]

Answer

given,

time interval = 11.3 s

a) initial velocity, vi = 15 m/s

   final velocity, v_f = -5.30 m/s

      a = \dfrac{v_f-v_i}{t}

      a = \dfrac{-5.30 -15}{11.3}

             a = -1.79 m/s²

   the direction is along left side

b)  initial velocity, vi = -5.30 m/s

   final velocity, v_f = -15 m/s

      a = \dfrac{v_f-v_i}{t}

      a = \dfrac{-15-(-5.30)}{11.3}

             a = -0.858 m/s²

   the direction is along left side

c) initial velocity, vi = 15 m/s

   final velocity, v_f = -15 m/s

      a = \dfrac{v_f-v_i}{t}

      a = \dfrac{-15-(15)}{11.3}

             a = -2.65 m/s²

   the direction is along left side

5 0
3 years ago
What is the process through which clouds are formed?
Illusion [34]

Answer:

dd

Explanation:

4 0
3 years ago
Read 2 more answers
What kind of chemical reaction does the chemical equation sodium + chlorine → sodium chloride represent?
RideAnS [48]
It is, A.combustion.
8 0
3 years ago
Read 2 more answers
The intensity of the sound from a certain source is measured at two points along a line from the source. The points are separate
Artemon [7]

Answer:

The source is at a distance of 4.56 m from the first point.

Solution:

As per the question:

Separation distance between the points, d = 11.0 m

Sound level at the first point, L = 66.40 dB

Sound level at the second point, L'= 55.74 dB

Now,

L = 10log_{10}\frac{I}{I_{o}}          

I = I_{o}10^{\frac{L}{10}} = I_{o}10^{0.1L} = 10^{- 12}\times 10^{0.1\times 66.40} = 10^{- 5.36}      

L' = 10log_{10}\frac{I'}{I_{o}}

I' = I_{o}10^{\frac{L'}{10}} = 10^{- 12}\times 10^{0.1\times 55.74} = 10^{- 6.426}        

where

I_{o} = 10^{- 12} W/m^{2}

I = Intensity of sound

Now,

I = \frac{P}{4\pi R^{2}}

Similarly,

I' = \frac{P}{4\pi (R + 11.0)^{2}}

Now,

\frac{I}{I'} = \frac{(R + 11.0)^{2}}{R^{2}}

\frac{10^{- 5.36}}{10^{- 6.426}} = \frac{(R + 11.0)^{2}}{R^{2}}

R ^{2} + 22R + 121 = 11.64R^{2}}

10.64R ^{2} - 22R - 121 = 0

Solving the above quadratic eqn, we get:

R = 4.56 m

8 0
3 years ago
A sperm whale can accelerate at about 0.0800 m/s 2 0.0800 m/s 2 when swimming on the surface of the ocean. How far will a sperm
Norma-Jean [14]

Answer:

26.64 m

Explanation:

Given the following :

Acceleration at ocean surface = 0.0800 m/s²

Distance covered if initial speed = 0.700 m/s and accelerates to a speed of 2.18m/s

Using the equation :

v² = u² + 2as

Where ;

v = final velocity ; u = initial velocity ; a = acceleration ; s = distance covered

Therefore,

v² = u² + 2as

2.18² = 0.7² + (2 × 0.08 × s)

4.7524 = 0.49 + 0.16s

4.7524 - 0.49 = 0.16s

4.2624 = 0.16s

s = 4.2624 / 0.16

s = 26.64 m

7 0
3 years ago
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