Answer: 2.86 m
Explanation:
To solve this question, we will use the law of conservation of kinetic and potential energy, which is given by the equation,
ΔPE(i) + ΔKE(i) = ΔPE(f) + ΔKE(f)
In this question, it is safe to say there is no kinetic energy in the initial state, and neither is there potential energy in the end, so we have
mgh + 0 = 0 + KE(f)
To calculate the final kinetic energy, we must consider the energy contributed by the Inertia, so that we then have
mgh = 1/2mv² + 1/2Iw²
To get the inertia of the bodies, we use the formula
I = [m(R1² + R2²) / 2]
I = [2(0.2² + 0.1²) / 2]
I = 0.04 + 0.01
I = 0.05 kgm²
Also, the angular velocity is given by
w = v / R2
w = 4 / (1/5)
w = 20 rad/s
If we then substitute these values in the equation we have,
0.5 * 9.8 * h = (1/2 * 0.5 * 4²) + (1/2 * 0.05 * 20²)
4.9h = 4 + 10
4.9h = 14
h = 14 / 4.9
h = 2.86 m
The answer is A. The resistance will be half(1/2R)
V=IR
R=V/I
If I is increased, R would decrease as R is inversely proportional to I.
Similarly, I is doubled by a factor of 2, R will decrease by a factor of 2.
Hope it helped!
Answer:
1.2 A of current will send (3.744 × 10¹⁸) ions to the cathode per second.
Explanation:
According to Faraday's second law of electrolysis, the amount of ions/mass of substance deposited at an electrode depends on its equivalent weight.
For a divalent ion, it will require 2F of electricity per mole.
1 F = 96500 C
Amount of electricity that passes through the electrolyte per second = (magnitude of current) × (time) = It = (1.2 × 1) = 1.2 C
2F (2×96500C) of electricity will deposit 1 mole of Copper ions
That is,
193000 C of electricity will deposit 1 mole of Copper.
1.2 C will deposit (1.2×1/193000); 0.0000062176 mole of Copper.
1 mole of Copper contains (6.022 × 10²³) ions according to the Avogadro's constant.
0.0000062176 mole of Copper will contain (0.0000062176 × 6.022 × 10²³) ions = (3.744 × 10¹⁸) ions.
Therefore, 1.2 A of current will send (3.744 × 10¹⁸) ions to the cathode per second.
Hope this Helps!!!
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