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2 years ago

A battery charger can produce 3A at 12 Volt and charges a battery fer 2 hr. Calculate work in KJ.

Physics

1 answer:

Oksi-84 [34.3K]2 years ago

4 0

Answer: 259.2 KJ

Explanation:

The formula calculate work don in a circuit is given by :-

$W=QV$ , where Q is charge and V is the potential difference.

The formula to calculate charge in circuit :-

$Q=It$ , where I is current and t is time.

Given : Current : $I=3A$

Potential difference : $V=12\ V$

Time : $t=2\ hr=2(3600)\text{ seconds}=7200\text{ seconds}$

Now, $Q=3(7200)=21,600\ C$

Then, $W=(21600)(12)=259,200\text{ Joules}=259.2\text{ KJ}$

Hence, the work done = 259.2 KJ

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Por una resistencia de 10 Ω fluyen 5A. ¿Cuál será la diferencia de potencial que se le debe aplicar a la resistencia?

ra1l [238]

Answer:

V = 50 volts

Explanation:

Given that,

Resistance, R = 10 ohms

Current, I = 5 A

We need to find the potential difference across the circuit. We know that,

V = IR

Put all the values,

V = 5 × 10

V = 50 volts

Hence, the potential difference is equal to 50 volts.

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2 years ago

17. Matthew has a piece of wood with mass of 278 g and a volume of 375 cm^3. What is the wood’s density? a. Step 1: Formula ____

Keith_Richards [23]

Answer:

Density =0.74 $g/cm^{3}$

Explanation:

Step 1: Formula

$Density=\frac{Mass}{Volume}$

Step 2: Data

m=278 g

v=375 $cm^{3}$

Step 3:Solve

d= $\frac{278}{375}$ $g/cm^{3}$

d=0.74 $g/cm^{3}$

8 0

2 years ago

A positively charged particle Q1 = +35nC is held fixed at the origin. A second charge of mass m = 3.5ug is floating a distance d

cupoosta [38]

Answer:

Explanation:

Q1 = 35 nC = 35 x 10^-9 C

m = 3.5 micro gram = 3.5 x 10^-9 Kg

d = 35 cm = 0.35 m

(a) The electrostatic force between the two charges is balanced by the weight of another charge.

F = m g

$\frac{1}{4\pi \epsilon _{0}}\frac{Q_{1}Q_{2}}{d^{2}}=mg$

$Q_{2}=\frac{4\pi \epsilon _{0}mgd^{2}}{Q_{1}}$

(b) By substituting the values

$Q_{2}=\frac{3.5\times 10^{-9}\times 9.8\times 0.35\timees 0.35}{9\times 10^{9}\times 35\times 10^{9}}$

Q2 = 13.34 x 10^-12 C

Q2 = 0.0134 nC

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3 years ago

A net force of Fnet acts on an object, causing the object to accelerate at a rat of 9m/s/s. what is the acceleration rate in a s

Readme [11.4K]

The new acceleration is c) 18m/s/s

Explanation:

Net force, mass and acceleration of an object are related by Newton's second law of motion:

$F=ma$

where

F is the net force on the object

m is its mass

a is its acceleration

In the first trial of this problem, a net force of $F_{net}$ is applied to the object, causing an acceleration of

$a=9 m/s^2$

Calling the mass of the object 'm', this means that

$F_{net} = ma = 9m$ [N] (1)

In the second trial, the force applied is $2F_{net}$ , so we have

$2F_{net} = ma'$

where a' is the new acceleration. Substituting (1) into the second equation, we find:

$2(9m) = ma' \rightarrow a' = 18 m/s^2$

This is because the acceleration is directly proportional to the force applied: therefore, if the force applied doubled, the acceleration doubles as well.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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3 years ago

A sled is at rest at the top of a slope 2 m high. The sled has a mass of 45 kg. What is the sled's potential energy?

kap26 [50]

Answer:

PE = 882 J

Explanation:

Through the International System we know that the gravity of the earth is 9.8 m/s², so...

Data:

m = 45 kg
g = 9.8 m/s²
h = 2 m
PE = ?

Formula:

$\boxed{\bold{PE=m*g*h}}$

Replace and solve:

$\boxed{\bold{PE=45\ kg*\ 9.8\frac{m}{s^{2}}*2\ m}}$

$\boxed{\boxed{\bold{PE=882\ J}}}$

The potential energy of the sled is <u>882 Joules</u>.

Greetings.

8 0

2 years ago