Answer:
The air difference was 11C while the water was less than 1C
Answer:
The urinary system removes excess substances and waste products from the metabolism from the body through the urine, contributing to the maintenance of homeostasis, the chemical composition of the internal environment. Urine is produced in the kidneys, passes through the ureters to the bladder, where it is stored and is released into the exterior through the urethra.
The kidneys perform the main work of the urinary system comparing with the other parts of the system, acting primarily as passageways and storage areas. With the filtration of blood and the formation of urine, the kidneys contribute to homeostasis of body fluids in a number of ways, such as: Regulation of the ionic composition of blood; Maintenance of blood osmolarity; Regulation of blood volume; Blood pressure regulation; PH regulation of blood; Hormone release; Regulation of blood glucose level; Waste excretion and toxic substances.
Ureters - They are two tubes that carry urine from the kidneys to the bladder. The ureters are capable of performing rhythmic contractions called peristalsis. Urine moves along the ureters in response to gravity and peristalsis.
Bladder - The urinary bladder acts as a temporary reservoir for urine storage. It is a hollow, elastic muscular organ that in men is directly anterior to the rectum and in women, is located in front of the vagina and below the uterus.
Urethra - is a tube that conducts urine from the bladder to the outside, being lined with mucosa that contains a large amount of mucus-secreting glands. The urethra opens outwards through the outer ostium of the urethra.
Answer: pretty sure they create islands.
Explanation: since they start underwater, they cool off and make islands? That’s what I remember.
Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.