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stepladder [879]
1 year ago
9

Classify the following alcohol as primary,

Chemistry
1 answer:
Nata [24]1 year ago
3 0

The classification of the alcohols gives;

  • Compound 1 - Primary alcohol
  • Compound 2 - Tertiary alcohol
  • Compound 3 - Secondary alcohol
  • Compound 4 - Secondary alcohol

<h3>What are alcohols?</h3>

Organic compounds occurs in families. The family of compounds is called a homologous series. The homologous series always have a functional group. The functional group is the atom, group of atoms or bond that is responsible for the chemical reactivity of the members of a given homologous series.

Now we know that the alcohols are those organic compounds that contains the -OH group. The could be aliphatic or alicyclic compounds. We shall now proceed to name the kind of alcohols that each of the compounds shown are;

  • Compound 1 - Primary alcohol
  • Compound 2 - Tertiary alcohol
  • Compound 3 - Secondary alcohol
  • Compound 4 - Secondary alcohol

Learn ore about alcohols:brainly.com/question/4698220

#SPJ1

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What is the answer please
xeze [42]

Answer:

Selenium

Explanation:

Oxygen is present in the group sixteen.

This group consist of oxygen, sulfur, selenium, tellurium and polonium.

All of these have same number of valance electrons thus they show similar properties.

From the given list of elements only selenium is belong to oxygen family thus it has properties similar to the oxygen.

Electronic configuration of oxygen:

O = [He] 2s² 2p⁴

Electronic configuration of selenium:

Se = [Ar] 3d¹⁰ 4s² 4p⁴

While aluminium, boron and phosphorus are belongs to other groups that's why their properties are not similar to the phosphorus.

phosphorus is present in group 15.

Boron and aluminium are present in group 13.

6 0
3 years ago
Please help- science
maks197457 [2]

Answer:

2. Full

Explanation:

A lunar eclipse occurs at a full moon when Earth is directly between the moon and the sun. During a lunar eclipse, Earth blocks sunlight from reaching the moon.

Hope this helps!!

8 0
2 years ago
Calculate the solubility product constant, Ksp, of lead(II) chloride, PbCl2, which has a
V125BC [204]

Answer:

0.0159m

Explanation:

9 M

Explanation:

Lead(II) chloride,  

PbCl

2

, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.

Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,  

K

sp

, will be established between the solid lead(II) chloride and the dissolved ions.

PbCl

2(s]

⇌

Pb

2

+

(aq]

+

2

Cl

−

(aq]

Now, the molar solubility of the compound,  

s

, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.

Notice that every mole of lead(II) chloride will produce  

1

mole of lead(II) cations and  

2

moles of chloride anions. Use an ICE table to find the molar solubility of the solid

 

PbCl

2(s]

 

⇌

 

Pb

2

+

(aq]

 

+

 

2

Cl

−

(aq]

I

 

 

 

−

 

 

 

 

 

0

 

 

 

 

 

0

C

 

 

x

−

 

 

 

 

(+s)

 

 

 

 

(

+

2

s

)

E

 

 

x

−

 

 

 

 

 

s

 

 

 

 

 

2

s

By definition, the solubility product constant will be equal to

K

sp

=

[

Pb

2

+

]

⋅

[

Cl

−

]

2

K

sp

=

s

⋅

(

2

s

)

2

=

s

3

This means that the molar solubility of lead(II) chloride will be

4

s

3

=

1.6

⋅

10

−

5

⇒

s

=  √ 1.6 4 ⋅ 10 − 5  = 0.0159 M

8 0
3 years ago
What is the molarity of a solution containing 56 grams of LiF in 959 mL of solution?
andrezito [222]

Answer:

2.25 M     <========= I do not see this in your selection of answers !

Explanation:

Mole weight of  Li F

      ( from periodic table ) = 6.94 + 18.998  = 25.938 gm/mole

56 gm / ( 25.938 gm /mole) = 2.15899 moles

2.15899 mole / (.959) L = 2.25 M

7 0
1 year ago
A sample of a compound containing only carbon and hydrogen atoms is completely combusted, producing
shusha [124]
It’s the last one C2H
5 0
3 years ago
Read 2 more answers
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