To get the ratio of the concentration of sodium acetate to the concentration of acetic acid we are going to use H-H equation:
when:
PH = Pka + ㏒[salt/acid]
when the Ka of acetic acid = 1.75 x 10^-5
so, we can get Pka from this formula:
Pka = -㏒Ka
= -㏒1.75 x 10^-5
= 4.76
and when we have PH = 5.75, so by substitution:
∴ 5.75 = 4.76 + ㏒[acetate/ acetic acid]
∴ [acetate/acetic acid] = 9.77
∴ the ratio of a concentration of acetate to acetic acid 9.77
Hey it's me again haha!
the answer to your question is:
answer: so f=20.1
a=8.2
m=?
f=ma
20.1 = 8.2*m in
20.1/8.2=m
so the answer is around 2.45 something!
also i'm sorry this question had be stumbled!
<span>Aluminum foil is a metal so it has the typycal properties of metals. These are the three most representative properties of metals that aluminum foil exhibit:
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</span><span>1) It is good conductor of electricity: this property is consequence of the metallic bond, which permits that the outermost electrons of each atom can flow through the entire network of atoms conducting the electricity.
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</span><span>2) Is is good conductor of heat: this other property of metals is due to transmission of vibration that is carried out between neighboring atoms.
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3) it is ductile: this property means that the metals can be formed into foils.
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<span>Other properties that can be mentioned are: solid at room temperature and mallealble (can form wires)
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Answer:
0.804g of NaHCO₃ you must add
Explanation:
pKa of HCO₃⁻/CO₃²⁻ is 10.32.
It is possible to find pH of a buffer by using H-H equation, thus:
pH = pka + log [A⁻] / [HA]
<em>Where [HA] is concentration of acid (HCO₃⁻) and [A⁻] is concentration of conjugate acid (CO₃²⁻).</em>
Moles of CO₃²⁻ = K₂CO₃ are:
4.00g ₓ (1mol / 138.206g) = 0.0289 moles CO₃²⁻
Replacing:
10.80 = 10.32 + log [0.0289] / [HCO₃⁻]
[HCO₃⁻] = 0.009570 moles you need to add to obtain the desire pH
As molar mass of NaHCO₃ is 84.007g/mol, mass of NaHCO₃ is:
0.009570 moles ₓ (84.007g / mol) =
<h3>0.804g of NaHCO₃ you must add</h3>
