1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tamiku [17]
4 years ago
11

Show a correct numerical setup for calculating the

Chemistry
1 answer:
valkas [14]4 years ago
7 0

0.25 moles of CO2 is present in 11 grams of CO2.

Explanation:

A mole represents the number of chemical entities in an element or molecule.

Number of moles of an element or molecule is determined by the formula:

The Number of moles (n) = weight of the atom given  ÷ atomic or molecular weight of the one mole of the element or molecule.

Themolar mass of one mole of carbon dioxide is:

12+ ( 16×2)

= 44 gram/mole

The given weight is 44 grams of carbon dioxide.

Putting the values in the equation,

n= 11 gms÷44 gms/ mole

n   = 0.25 mole

You might be interested in
Calculate the amount of time required to raise temperature of 0.50 liter of water from
Burka [1]
<h3>Answer:</h3>

19 seconds

<h3>Explanation:</h3>

Heat energy was supplied and used to heat 0.50 liters of water from 0°C to 10°C.

This means water gained heat energy that was supplied.

Therefore;

Heat supplied = Heat gained by water

We are required to calculate the time taken to raise the temperature of water from 0°C to 10°C.

Step 1: Calculate the heat gained by water

Quantity of heat = Mass × specific heat capacity × change in temperature

Density of water 1 g/ml

Volume of water is 500 mL

Therefore, since Mass = density × volume

The mass of water = 500 g

Change in temperature = 10° C

Specific heat capacity of water = 4.18 J/g/°C

Thus;

Quantity of heat = 500 g × 4.18 J/g/°C × 10

                           = 20,900 Joules

Step 2: Heat supplied by a heater

Heat supplied = Power × time

Power = 1100 J/s

Assuming the time required is x

Heat supplied = 1100x Joules

Step 3: Time required

Remember; heat supplied = heat gained by water

Therefore;

1100x joules = 20,900 Joules

      x = 20,900/1100

        = 19 seconds

Therefore, the time required to raise the temperature of water from 0°C to 10°C is 19 seconds.

6 0
3 years ago
Significant digits and scientific notation!
tiny-mole [99]

See the image below.

6 0
3 years ago
How are the properties of thermosoftening and thermosetting polymers different? Use ​ideas about the structures of these two typ
stepan [7]

Thermosoftening plastics melt when they are heated.This means that they can be recycled , which involves melting them before making a new product. Thermosoftening plastics do not have covalent bonds between neighbouring polymer molecules, so the molecules can move over each other when heated and the plastic melts.

7 0
3 years ago
What is the interaction between two charged particles called?
Roman55 [17]
Your answer might be Electromagnetism
5 0
3 years ago
Read 2 more answers
The dissociation of calcium carbonate has an equilibrium constant of Kp= 1.20 at 800°C. CaCO3(s) ⇋ CaO(s) + CO2(g)
Fed [463]

Explanation:

(a)   Formula that shows relation between K_{c} and K_{p} is as follows.

                 K_c = K_p \times (RT)^{-\Delta n}

Here, \Delta n = 1

Putting the given values into the above formula as follows.

        K_c = K_p \times (RT)^{-\Delta n}

                  = 1.20 \times (RT)^{-1}

                  = \frac{1.20}{0.0820 \times 1073}

                  = 0.01316

(b) As the given reaction equation is as follows.

               CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)

As there is only one gas so ,

                p[CO_{2}] = K_{p} = 1.20

Therefore, pressure of CO_{2} in the container is 1.20.

(c)   Now, expression for K_{c} for the given reaction equation is as follows.  

             K_{c} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}

                        = \frac{x \times x}{(a - x)}

                        = \frac{x^{2}}{(a - x)}[/tex]

where,    a = initial conc. of CaCO_{3}

                  = \frac{22.5}{100} \times 9.56

                  = 0.023 M

          0.0131 = \frac{x^{2}}{0.023 - x}

                  x = 0.017

Therefore, calculate the percentage of calcium carbonate remained as follows.

       % of CaCO_{3} remained = (\frac{0.017}{0.023}) \times 100

                                  = 75.46%

Thus, the percentage of calcium carbonate remained is 75.46%.

3 0
4 years ago
Other questions:
  • What is the magnitude of the dipole moment formed by separating a proton and an electron by 85 pm ?
    8·1 answer
  • What is true of every water molecule?It is made of two water atoms.It is made of one water atom and one DNA atom.It is made of t
    11·1 answer
  • How do I identify the ions present in K2HPO4?
    13·1 answer
  • How many grams of the molecule (C2H4O2) would be required to make 1 L of a 0.5 M solution of the molecule? (Carbon = 12, Oxygen
    7·1 answer
  • In the reaction 2H2O2 -&gt; 2H2O + O2, if you start with 4 H2O2, how much O2 will you end up with?
    8·1 answer
  • 9 Cardiac disease is a major problem in the United States."
    7·1 answer
  • Glucose has formula C6 H12 O6.<br>Calculate the number of Oxygen atoms present in 18 g of glucose​
    9·2 answers
  • A chemist prepares a solution of barium chlorate BaClO32 by measuring out 33.0 umol of barium chlorate into a 500.0 mL volumetri
    8·1 answer
  • 2.Heating causes a substance to lose thermal energy.
    9·1 answer
  • if u could buy 500 individual nerds candies for $5 or 186 g of individual nerds candies for 5, which would be better ? why?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!