All categories

2 years ago

A charged point particle is placed at the center of a spherical gaussian surface. the electric flux is changed if:

Physics

1 answer:

ololo11 [35]2 years ago

3 0

The electric flux is changed only if we change the charge.

<h3>What is the expression of electric flux?</h3>

As per gauss law, total electric flux link through a surface is equal to (1/ε0) × charge.
Mathematically, electric flux = q/ε0
q = total charge enclosed by the gaussian surface
Here the electric flux is directly proportional to the charge, so on changing charge, the electric flux changes.

Thus, we can conclude that the electric flux is changed only if we change the charge.

Learn more about the gauss law here:

brainly.com/question/13434428

#SPJ1

You might be interested in

A runner circles the track exactly 2 times for distance of 800m. it takes 4.0min. what is her average speed in m/s? what is her

Sindrei [870]

If the runner ends where she started, then her total displacement is $\Delta x=0\,\mathrm m$ , which means her average velocity will be

$\bar v=\dfrac{\Delta x}{\Delta t}=\dfrac{0\,\mathrm m}{4.0\,\mathrm{min}\cdot\frac{60\,\mathrm s}{1\,\mathrm{min}}=0\,\dfrac{\mathrm m}{\mathrm s}$

The total distance she traversed, however, was $\Delta d=800\,\mathrm m$ , which gives her an average speed of

$\bar s=\dfrac{\Delta d}{\Delta t}=\dfrac{800\,\mathrm m}{4.0\,\mathrm{min}\cdot\frac{60\,\mathrm s}{1\,\mathrm{min}}=3.3\,\dfrac{\mathrm m}{\mathrm s}$

5 0

3 years ago

If a capital letter R is seen in an ordinary mirror , what does it look like?

Radda [10]

Answer:

........................

7 0

2 years ago

Read 2 more answers

What was the most serious money problem faced by people in the early United States?

alexira [117]

♥B. There was no single medium of exchange.♥
Take a look at the saying "Not worth a Continental".
It referrers to the fact that currency issued by the Continental Congress was usually just a promise to pay.
Leaving your answer with ♥B♥

5 0

3 years ago

A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 19

Hunter-Best [27]

The car will take 300 m before it stops due to applying break.

<h3>What's the relation between initial velocity, final velocity, acceleration and distance?</h3>

As per Newton's equation of motion, V² - U² = 2aS
V= final velocity velocity of the object, U = initial velocity velocity of the object, a= acceleration, S = distance covered by the object
Here, U = 60 ft/sec, V = 0 m/s, a= -6 ft/sec²
So, 0² - 60² = 2×6× S

=> -3600 = -12S

=> S = 3600/12 = 300 m

Thus, we can conclude that the distance covered by the car is 300 m before it stopped.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 6 ft/sec². How long will it take before the car stops?

Learn more about the Newton's equation of motion here:

brainly.com/question/8898885

#SPJ1

7 0

2 years ago

State coulombs law in word

amid [387]

<h2>state coulombs law in word</h2>

: a statement in physics: the force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them

hope it helps

#carry on learning

3 0

3 years ago