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Ilya [14]
2 years ago
15

If a capital letter R is seen in an ordinary mirror , what does it look like?

Physics
2 answers:
Radda [10]2 years ago
7 0

Answer:

D

........................

AleksAgata [21]2 years ago
5 0
D would be the correct awnser it would just be a reflection
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A 645 g block is released from rest at height h0 above a vertical spring with spring constant k = 530 N/m and negligible mass. T
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Answer:

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b)  Workdone by the spring = - Workdone by the block = -5.88J

c) Taking x = 0 at the contact point we have U top = U bottom

So, mgh_o = \frac{1}{2}kx² - mgx

And, h_o= ( \frac{1}{2}kx² - mgx )/(mg) = [\frac{1}{2} (530)(0.149^2)-(0.645)(9.8)(0.149)]/(0.645x9.8)    

   h_o=   0.78m            

d) Now, if the initial initial height of block is 3h_o

h_o = 3 x 0.78 = 2.34m

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\frac{1}{2}(530)x²  - [(0.645)(9.8)x] - [(0.645)(9.8)(2.34) = 0

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a=265

b=-6.321

c=-14.8

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x= 0.24 or x=-0.225

Considering only positive root:

x= 0.24m (maximum  compression of the spring)

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