Answer:
The angular acceleration is 10.10 rad/s².
Explanation:
Given that,
Mass of sphere =220 g
Diameter = 4.50 cm
Friction force = 0.0200 N
Suppose we need to find its angular acceleration.
We need to calculate the angular acceleration
Using formula of torque
![\tau=f\times r](https://tex.z-dn.net/?f=%5Ctau%3Df%5Ctimes%20r)
![I\times\alpha=f\times r](https://tex.z-dn.net/?f=I%5Ctimes%5Calpha%3Df%5Ctimes%20r)
Here, I = moment of inertia of sphere
![\dfrac{2}{5}mr^2\times\alpha=f\times r](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B5%7Dmr%5E2%5Ctimes%5Calpha%3Df%5Ctimes%20r)
![\alpha=\dfrac{5\times f}{2mr}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B5%5Ctimes%20f%7D%7B2mr%7D)
Put the value into the formula
![\alpha=\dfrac{5\times0.0200}{2\times220\times10^{-3}\times2.25\times10^{-2}}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B5%5Ctimes0.0200%7D%7B2%5Ctimes220%5Ctimes10%5E%7B-3%7D%5Ctimes2.25%5Ctimes10%5E%7B-2%7D%7D)
![\alpha=10.10\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D10.10%5C%20rad%2Fs%5E2)
Hence, The angular acceleration is 10.10 rad/s².
Answer:
NE DIYON INGILIZ MISIN SEN