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aliina [53]
3 years ago
11

A three-toed sloth travels eastward across a tree limb at 0.11 km/hr. After 30.0 minutes, what is the displacement of the sloth?

Physics
2 answers:
ozzi3 years ago
7 0

Answer:

55 m eastward

Explanation:

The relationship between velocity, displacement and time is:

v=\frac{d}{t}

where v is the velocity, d the displacement and t the time.

In this problem, we know:

- v=0.11 km/h eastward is the velocity of the sloth

- t=30.0 min = 0.5 h is the time of the motion

Therefore, we can find the displacement of the sloth by re-arranging the previous formula:

d=vt=(0.11 km/h)(0.5 h)=0.055 km = 55 m

and the direction is the same as the velocity (eastward).

babunello [35]3 years ago
3 0
Displacement is the total distance from the start point, so what you want to say is that in total, <span>If he moves 0.11 km in 60 minutes (km/h) then in 30 minutes he simply moved 0.055 km (half of 0.11 km) </span>
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A spectral line from a star is observed to have a wavelength of 656.5 nm. The rest wavelength of this line is 656.8 nm. (a) What
nignag [31]

Answer:

speed of star is  1.37 × 10^{5} m/s

it is approaching to earth because wavelength of star is decreasing than rest

if emit same wavelength it does not move anywhere

it will remain steady condition with respect earth

Explanation:

given data

wavelength = 656.5 nm

rest wavelength = 656.8 nm

to find out

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solution

we know here equation that is

wavelength shift / wavelength at rest  = velocity of source / speed of light

so put all value and find

velocity of source = 3 × 10^{-9} × 3 × 10^{8} / 656.8 × 10^{-9}

velocity of source star = 1.37 × 10^{5} m/s

and

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and

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6 0
3 years ago
How can you find the nuetrons in youre element ??
miskamm [114]

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Explanation:

5 0
2 years ago
A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q separated by a distance s.
marishachu [46]

Answer:

a) the magnitude of the force is

F= Q(\frac{kqs}{r^3}) and where k = 1/4πε₀

F = Qqs/4πε₀r³

b)  the magnitude of the torque on the dipole

τ = Qqs/4πε₀r²

Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

where k = 1/4πε₀

the expression of the electric field due to dipole at a distance r is

E(r) = \frac{kp}{r^{3} } , where p = q × s

E(r) = \frac{kqs}{r^{3} } where r>>s

a) find the magnitude of force due to the dipole

F=QE

F= Q(\frac{kqs}{r^3})

where k = 1/4πε₀

F = Qqs/4πε₀r³

b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces

τ = F sinθ × s

θ = 90°

note: sin90° = 1

τ = F × r

recall  F = Qqs/4πε₀r³

∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

8 0
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Therefore, the first option is correct.
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