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Sav [38]
3 years ago
8

HELP WHAT IS THE SLOPE!!!!!

Mathematics
1 answer:
babunello [35]3 years ago
4 0
If the lines are parallel, they should have the same slope. So in this case would be -5/3
Hope this helps!
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Use the coordinates of the labeled point to find the point-slope equation of the line.
liraira [26]

Answer:

C. y+5=-4(x-2)

Step-by-step explanation:

5 0
3 years ago
Solve 3 + 4x > -5 for x
Debora [2.8K]

you have the following inequality:

3 + 4x > -5

in order to solve for x, proceed as follow:

3 + 4x > -5 subtract 3 both sides

4x > - 5 - 3

4x > -8 divide by 4 both sides

x > -8/4

x > -2

Hence, the solution to the given inequality is x > -2

7 0
1 year ago
I need help with this math question
givi [52]

Answer:

a.) y = 3/(2ˣ)

b.) y = 1/(2ˣ)

c.) y = (π^π)ˣ

d.) y = (1/27)(1/√(3))ˣ

e.) y = .002908/(.119025ˣ)

f.) y = .00000004808/(.0413ˣ)

Step-by-step explanation:

Concept need to know is:

  • a negative exponent will flip the numerator with the denominator
  • a fraction as an exponent is just a root. so if the exponent is x^(1/2) then the root is 2 and x^(1/3) is a cube root
  • adding and subtracting exponent is the same thing as multiplying the same base.
  • so x^(1+2) = (x^1)(x^2)
  • and x^(1-2) = (x^1)(x^-2)

7 0
3 years ago
The line is given by equation y–1.5x = c. What is the value of c if the line passes through the point K (2, –3).
aleksandr82 [10.1K]

Answer:

c = -6

Step-by-step explanation:

To find the value of c to make the line pass through the point K = (2, -3), we just need to use the values of x = 2 and y = -3 in the equation, then we find the value of c.

So, we have that:

y - 1.5*x = c

(-3) - 1.5 * (2) = c

-3 - 3 = c

c = -6

So the value of c is -6

To check if the value is correct, we can use the value x = 2 and see if the value of y is -3:

y - 1.5*x = -6

y - 1.5*2 = -6

y - 3 = -6

y = -6 + 3 = -3

So it's correct.

7 0
3 years ago
Read 2 more answers
Can some one help me plzz!! No links!!​
Alona [7]
The answer is C.0,3 because One of Y equal 0 for X
5 0
3 years ago
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