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leonid [27]
2 years ago
13

To lower the risk of a collision, you should keep at least __________ of space to one side of your vehicle at all times.

Physics
1 answer:
Novosadov [1.4K]2 years ago
7 0

One must keep one car width of space to side of vehicle to avoid collision.

What is collision?

Collision is the sudden striking of two bodies that exerts forces on each other thus acelerating the objects in relatively very short time. One must maintain atleast one car width of space to side of vehicle to lower the risk of collision. If the space is lower than one car width than you should lower the speed of car to avoid collision.

One can also follow the two second disciple to avoid collision. According to this rule, the car should maintain two second safe distance behind any other vehicle .It acts as a safety buffer or defensive mechanism to avoid the risk of collision at all times at any speed. Also according to impulse momentum change theorem, the force on each object can be minimized by maintaing  more distance. As force and time are inversely proportional in collision.

Therefore, one car width distance is the safest minimum distance to avoid risks of collision .

Learn more about collision here:

brainly.com/question/14439547

#SPJ1

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Kim throws a beach ball up in the air. It reaches its maximum height 0.50s later. We can ignore air resistance. What was the bea
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Answer:

The beach ball's velocity at the moment it was tossed into the air is <u>4.9 m/s.</u>

Explanation:

Given:

Time taken by the ball to reach maximum height is, t=0.50\ s

We know that, velocity of an object at the highest point is always zero. So, final velocity of the ball is, v=0\ m/s

Also, acceleration acting on the ball is always due to gravity. So, acceleration of the ball is, a=g=-9.8\ m/s^2

The negative sign is used as acceleration is a vector and it acts in the downward direction.

Now, we have the equation of motion relating initial velocity, final velocity, acceleration and time given as:

v=u+at

Where, 'u' is the initial velocity.

Plug in the given values and solve for 'u'. This gives,

0=u-9.8(0.5)\\u=9.8\times 0.5\\u=4.9\ m/s

Therefore, the beach ball's velocity at the moment it was tossed into the air is 4.9 m/s

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When there are more electrons the result it a negative ion, and when there are more protons it is a positive ion. 
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hope this helps you

have a nice day:)

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