Answer: 1. The movie one is virtual and the bathroom mirror is real
2. The image is distorted in a way
3. Behind the spoon
Explanation:
Answer:
3. 3.5 s
Explanation:
The position of traveller A is given by the equation:

where
is the acceleration of A
t is the time measured from when A started the motion
The position of traveller B instead is given by

where a (acceleration) is the same as traveller A, and

is B's initial velocity. We can verify that the formula is correct by substituting t=2, and we get
, which means that B starts its motion 2 seconds later.
Traveller B overtakes traveller A when the two positions are the same, so:

Covalent bonds form when electrons are shared between atoms and are attracted by the nuclei of both atoms. In pure covalent bonds, the electrons are shared equally. In polar covalent bonds, the electrons are shared unequally, as one atom exerts a stronger force of attraction on the electrons than the other.
Sound level at distance of 15 m is given as 20 dB
so intensity at this distance is given as



now if we move closer to some some distance the sound level is now 50 dB
now the intensity is given as



now we know that



so now the distance from friend must be 47 cm
When you are going down you pick up more speed