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3 years ago

Which describes the rotational motion of a planet?

1 answer:

4 0

<span>B.) The motion of the planet as it spins on its axis

Please be careful with option A, 'cause it is "Revolutionary motion", many people would choose that but, it's wrong.

In short, Your Answer would be Option B

Hope this helps!</span>

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A 2.30-kg cylindrical rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end. a solid sph

Marina86 [1]

Solution:

initial sphere mvr = final sphere mvr + Iω
where I = mL²/3 = 2.3g * (2m)² / 3 = 3.07 kg·m²
0.25kg * (12.5 + 9.5)m/s * (4/5)2m = 3.07 kg·m² * ω
where: ω = 2.87 rad/s

So for the rod, initial E = KE = ½Iω² = ½ * 3.07kg·m² * (2.87rad/s)²
E = 12.64 J becomes PE = mgh, so
12.64 J = 2.3 kg * 9.8m/s² * h
h = 0.29 m

h = L(1 - cosΘ) → where here L is the distance to the CM
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ
Θ = arccos((1-0.29)/1) = 44.77 º

8 0

3 years ago

Q7) A box sliding with a velocity of 5 m/s accelerates at 2 m/s^2. How

grigory [225]

Answer:

The box displacement after 6 seconds is 66 meters.

Explanation:

Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object ( $\Delta s$ ), in meters, can be determined by the following expression:

$\Delta s = v_{o}\cdot t+\frac{1}{2}\cdot a\cdot t^{2}$ (1)

Where:

$v_{o}$ - Initial velocity, in meters per second.

$t$ - Time, in seconds.

$a$ - Acceleration, in meters per square second.

If we know that $v_{o} = 5\,\frac{m}{s}$ , $t = 6\,s$ and $a = 2\,\frac{m}{s^{2}}$ , then the box displacement after 6 seconds is:

$\Delta s = 66\,m$

The box displacement after 6 seconds is 66 meters.

5 0

3 years ago

A shot-putter accelerates a 7.2 kg shot from rest to 17 m/s . what work did the shot-putter do on the ball?

garri49 [273]

<span>1.0x10^3 Joules The kinetic energy a body has is expressed as the equation E = 0.5 M V^2 where E = Energy M = Mass V = Velocity Since the shot was at rest, the initial energy is 0. Let's calculate the energy that the shot has while in motion E = 0.5 * 7.2 kg * (17 m/s)^2 E = 3.6 kg * 289 m^2/s^2 E = 1040.4 kg*m^2/s^2 E = 1040.4 J So the work performed on the shot was 1040.4 Joules. Rounding the result to 2 significant figures gives 1.0x10^3 Joules</span>

6 0

3 years ago

Calculate the momentum of a 1800 kg elephant charging a hunter at a speed of 7.50 m/s.

liq [111]

The amount of movement, linear momentum, momentum or momentum is a physical quantity derived from a vector type that describes the movement of a body in any mechanical theory. In classical mechanics, the amount of movement is defined as the product of body mass and its velocity at a given time.

p= mv

Where,

m = mass

v = Velocity

Our values are given as,

$m = 1800kg$

$v = 7.5m/s$

Replacing we have that,

$p = (1800)(7.5)$

$p = 13500kg\cdot m/s$

Therefore the momentum is $13500kg\cdot m/s$

8 0

3 years ago

A woman takes her dog rover for a walk on a leash. She pulls on the leash with a force of 30.0 N at an angle of 29° above the ho

IrinaK [193]

19.8 N force is tending to lift Rover vertically off the ground.

<h3>What is horizontal and vertical component?</h3>

The horizontal velocity component ( $v_{x}$ ) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component ( $v_{y}$ ) describes the influence of the velocity in displacing the projectile vertically.