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cestrela7 [59]
1 year ago
8

Compare the frequency, wavelength, and radiant energy of yellow visible light to that of purple visible light.

Physics
1 answer:
dybincka [34]1 year ago
4 0

Answer:

Violet has a higher frequency (approximately 7.5×1014 Hz 7.5 × 10 14 Hz ) than red light (approximately 4.3×1014 Hz 4.3 × 10 14 Hz ). Since the speed of both waves is the same, we infer that violet has a shorter wavelength (400 nm ) than red (700 nm ).

Explanation:

hope it helps this took a lot of my time please mark brainlets!

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Turning on a light switch converts mechanical energy to electrical and radiant energy. So Mechanical energy
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Two hockey pucks on an ice rink are held together with a compressed spring between them. The pucks are released and the spring p
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Where the m1 and m2 is the mass of two object. U1 and U2 are the initial velocity of hockey pucks. V1 and V2 are the final velocity of Hockey Pucks.

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1. In an experiment, a positively charged oil droplet weighing 6.5 x 10-15 N is held stationary
blagie [28]

The charge on the droplet must be 1.2\cdot 10^{-18} C

Explanation:

In order for the oil droplet to be in equilibrium, the force of gravity acting on it (the weight, acting downward) must be equal to the electrical force acting upward.

The gravitational force is:

F_g = 6.5 \cdot 10^{-15} N

which is equivalent to the weight of the droplet.

The electric force is given by:

F_E = qE

where

q is the charge on the oil droplet

E=5.3\cdot 10^3 N/C is the magnitude of the electric field

Since the two forces must be equal,

F_G = F_E\\F_G = qE

And solving for q,

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Learn more about gravitational force and electric force:

brainly.com/question/1724648

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What makes plants the beginning of the food chain
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A rotating merry-go-round makes one complete revolution in 4.0s a) what is the linear speed of a child seated 1.2 meters from th
lianna [129]

Answer:a) The linear speed of the rotating merry-go-round is 1.884 m/s.

b) The acceleration of the rotating merry-go-round  device is 2.95m/s^2.

Explanation:

a) linear speed of the device:

Distance =2\pi (r)

Child seated 1.2 meters from the center, which means that radius ,r = 1.2 meters

Time taken to complete one revolution = 4.0 seconds

\text{Linear speed}=v=\frac{distance}{time}=\frac{2\pi r}{t}=\frac{2\times 3.14\times 1.2 m}{4.0 s}=\frac{7.536 m}{4.0 s}=1.884 m/s

The linear speed of the rotating merry-go-round is 1.884 m/s.

b) Acceleration

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=\frac{1.884 m/s\times 1.884m/s}{1.2 m}=2.95m/s^2

The acceleration of the rotating merry-go-round  device is 2.95m/s^2.

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