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4 years ago

What are some similarities between heat and temperature?

2 answers:

7 0

<span><u>Answer </u>
Heat is a form of energy while temperature is the measure or degree of coldness or hotness of a substance, place or something.
The similarities between heat and temperature are:
1. Heat causes the temperatures to raise. This means that it is the heat energy that causes temperatures to change.
2. Both heat and temperatures can be measured by specific units. Heat is measured in joules while temperature is measured in kelvin.
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kow [346]4 years ago

6 0

By definition, we have:

Heat:

Energy that is manifested by an increase in temperature and comes from the transformation of other energies; is originated by the vibratory movements of the atoms and the molecules that form the bodies

Temperature:

The temperature is a magnitude referred to the common notions of heat measurable by a thermometer. In physics, it is defined as a scalar quantity related to the internal energy of a thermodynamic system

Some similarities are:

1) The more heat there is, the higher the temperature.

2) The less heat there is, the lower the temperature.

3) Mathematically the heat and the temperature difference between two points are proportional.

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MrMuchimi

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3 years ago

A woman is 1.6 m tall and has a mass of 50 kg. She moves past an observer with the direction of the motion parallel to her heigh

eduard

To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.

By definition we know that the relative velocity of an object with reference to the Light, is defined by

$V_0 = \frac{V}{\sqrt{1-\frac{V^2}{c^2}}}$

Where,

V = Speed from relative point

c = Speed of light

On the other hand we have that the linear momentum is defined as

P = mv

Replacing the relative velocity equation here we have to

$P = \frac{mV}{\sqrt{1-\frac{V^2}{c^2}}}$

$P^2 = \frac{m^2V^2}{1-\frac{V^2}{c^2}}$

$P^2 = \frac{P^2V^2}{c^2}+m^2V^2$

$P^2 = V^2 (\frac{P^2}{c^2}+m^2)$

$V^2 = \frac{P^2}{\frac{P^2}{c^2}+m^2}$

$V^2 = \frac{(2.1*10^10)^2}{\frac{(2.1*10^10)^2}{(3.8*10^8)^2}+50^2}$

$V = 2.81784*10^8m/s$

Therefore the height with respect the observer is

$l = l_0*\sqrt{1-\frac{V^2}{c^2}}$

$l = 1.6*\sqrt{1-\frac{(2.81*10^8)^2}{(3*10^8)^2}}$

$l = 0.56m$

Therefore the height which the observerd measure for her is 0.56m

8 0

3 years ago

While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83

allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

$\beta_{dB} = 10log_{10}\frac{I}{I_0}$