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Eduardwww [97]
3 years ago
12

What are some similarities between heat and temperature? 

Physics
2 answers:
dalvyx [7]3 years ago
7 0
<span><u>Answer </u>
Heat is a form of energy while temperature is the measure or degree of coldness or hotness of a substance, place or something.
The similarities between heat and temperature are:
1. Heat causes the temperatures to raise. This means that it is the heat energy that causes temperatures to change.
2. Both heat and temperatures can be measured by specific units. Heat is measured in joules while temperature is measured in kelvin.  
</span>
kow [346]3 years ago
6 0

By definition, we have:

Heat:

Energy that is manifested by an increase in temperature and comes from the transformation of other energies; is originated by the vibratory movements of the atoms and the molecules that form the bodies

Temperature:

The temperature is a magnitude referred to the common notions of heat measurable by a thermometer. In physics, it is defined as a scalar quantity related to the internal energy of a thermodynamic system

Some similarities are:

1) The more heat there is, the higher the temperature.

2) The less heat there is, the lower the temperature.

3) Mathematically the heat and the temperature difference between two points are proportional.

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What is the mechanical energy of a 500kg rollercoaster car moving with a speed of 3m/s at the top hill that is 30m high
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3 years ago
An airplane is moving at 350 km/hr. If a bomb is
bogdanovich [222]

Answers:

a) -171.402 m/s  

b) 17.49 s

c) 1700.99 m

Explanation:

We can solve this problem with the following equations:

y=y_{o}+V_{oy}t-\frac{1}{2}gt^{2} (1)

x=V_{ox}t (2)

V_{f}=V_{oy}-gt (3)

Where:

y=0 m is the bomb's final height

y_{o}=1.5 km \frac{1000 m}{1 km}=1500 m is the bomb's initial height

V_{oy}=0 m/s is the bomb's initial vertical velocity, since the airplane was moving horizontally

t is the time

g=9.8 m/s^{2} is the acceleration due gravity

x is the bomb's range

V_{ox}=350 \frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=97.22 m/s is the bomb's initial horizontal velocity

V_{f} is the bomb's final velocity

Knowing this, let's begin with the answers:

<h3>b) Time </h3>

With the conditions given above, equation (1) is now written as:

y_{o}=\frac{1}{2}gt^{2} (4)

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (5)

t=\sqrt{\frac{2 (1500 m)}{9.8 m/s^{2}}} (6)

t=17.49 s (7)

<h3>a) Final velocity </h3>

Since V_{oy}=0 m/s, equation (3) is written as:

V_{f}=-gt (8)

V_{f}=-(97.22)(17.49 s) (9)

V_{f}=-171.402 m/s (10) The negative sign only indicates the direction is downwards

<h3>c) Range </h3>

Substituting (7) in (2):

x=(97.22 m/s)(17.49 s) (11)

x=1700.99 m (12)

5 0
3 years ago
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