I would say by putting two fingers under your chin or putting two fingers on the back of your wrist, hope i helped ! :)
Answer:
It is an SI unit
Explanation:
The metre is defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second. The metre was originally defined in 1793 as one ten-millionth of the distance from the equator to the North Pole
Answer:
Complete this sentence. If the mass of object A is greater than object B, then the weight of object A will be heavier the weight of object B.
Explanation:
If the mass of Object A is more/greater than object B then it would be "heavier"
The boat traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.
Explanation:
Velocity is a physical quantity that describes the rate of change of displacement with time.
Velocity = 
The quantity differs from speed in that it has both magnitude and direction.
From the options given above:
Displacement: The boat traveled in the north direction from the dock to a 200m mark.
Time taken: approximately less than 5 minutes was the duration of traveling.
This describes the boat's velocity accurately.
Learn more:
Velocity
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Answer:
Explanation:
The energy of Mass-Spring System the sum of the potential energy of the block plus the kinetic energy of the block:

Where:

There are two cases, the first case is when the spring is compressed to its maximum value, in this case the value of the kinetic energy is zero, since there is no speed, so:

The second case is when the block passes through its equilibrium position, in this case the elastic potential energy is zero since
, so:

Now, let's find the energy of the system when the block is replaced by one whose mass is twice the mass of the original block using the previous data:

Where in this case:

Therefore:
