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3 years ago

How to live a life like scientists

Physics

2 answers:

Fofino [41]3 years ago

5 0

↓↓

Question Authority. ...
Think Creatively. ...
Overcome Limits. ...
Brave criticism.

Explanation:

<h3>How To Live Your Life Like A Scientist?</h3>

→A scientist is someone who studies or has expertise in science. More generally, they are people who love figuring out how or why things happen. They conduct research in an area of interest to advance our understanding of nature. The fruits of their labour make ordinary life a rich, comfortable and overall a worthwhile experience.

→Throughout history, we have witnessed that scientists have propelled our society forwards. Wouldn't it be better then if everyone lived their lives more scientifically? In this post, we will explore what it would mean to live life like a scientist.

<h2>#CARETOLEARN❤️</h2>

kolezko [41]3 years ago

3 0

Answer:

Scientific thinking skills are very important for getting along in life. They allow you to analyse problems or situations you find yourself involved in that don't always have an easy or obvious answer. We all run into problems in relationships, at work, when learning new things, when seeking to advance our lives etc.

You must not be afraid to question authority, especially when they are wrong, you must think creatively, think out-of-the-box, overcome limits and most importantly accept criticism a part of life. These traits of a scientist will build a distinctive personality in an otherwise boring existence.

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3. Provide two examples of static electric charge.

Rzqust [24]

Answer: 1. walking across a carpet and touching a metal door handle 2. pulling your hat off and having your hair stand on end.

Explanation

5 0

3 years ago

Calculate the pressure exerted by a 4000N camel on the sand. The camel’s feet have a

Harrizon [31]

Answer:

The pressure exerted by camel feet is <u>2000 N/m²</u>.

Step-by-step explanation:

<h3><u>Solution</u> :</h3>

Here, we have given that ;

Force applied on camel feet = 4000 N
Total area of camel feet = 2 m²

We need to find the pressure exerted by camel feet.

As we know that :

${\longrightarrow{\pmb{\sf{Pressure= \dfrac{Area}{Force}}}}}$

Substituting all the given values in the formula to find the pressure exerted by camel feet.

$\begin{gathered} \begin{array}{l} {\longrightarrow{\sf{Pressure= \dfrac{Area}{Force}}}} \\ \\ {\longrightarrow{\sf{Pressure= \dfrac{4000}{2}}}} \\ \\ {\longrightarrow{\sf{Pressure= \cancel{\dfrac{4000}{2}}}}} \\ \\ {\longrightarrow{\sf{Pressure= 2000 \: N/{m}^{2}}}} \\ \\\star \: \small\underline{\boxed{\sf{\purple{Pressure= 2000 \: N/{m}^{2}}}}} \end{array}\end{gathered}$

Hence, the pressure exerted by camel feet is 2000 N/m².

$\rule{300}{2.5}$

3 0

2 years ago

Now let’s apply the work–energy theorem to a more complex, multistep problem. In a pile driver, a steel hammerhead with mass 200

andrew11 [14]

Answer:

a) v = 7.67

b) n = 81562 N

Explanation:

Given:-

- The mass of hammer-head, m = 200 kg

- The height at from which hammer head drops, s12 = 3.00 m

- The amount of distance the I-beam is hammered, s23 = 7.40 cm

- The resistive force by contact of hammer-head and I-beam, F = 60.0 N

Find:-

(a) the speed of the hammerhead just as it hits the I-beam and

(b) the average force the hammerhead exerts on the I-beam.

Solution:-

- We will consider the hammer head as our system and apply the conservation of energy principle because during the journey of hammer-head up till just before it hits the I-beam there are no external forces acting on the system:

ΔK.E = ΔP.E

K_2 - K_1 = P_1- P_2

Where, K_2: Kinetic energy of hammer head as it hits the I-beam

K_1: Initial kinetic energy of hammer head ( = 0 ) ... rest

P_2: Gravitational potential energy of hammer head as it hits the I-beam. (Datum = 0)

P_1: Initial gravitational potential energy of hammer head

- The expression simplifies to:

K_2 = P_1

Where, 0.5*m*v2^2 = m*g*s12

v2 = √(2*g*s12) = √(2*9.81*3)

v2 = 7.67 m/s

- For the complete journey we see that there are fictitious force due to contact between hammer-head and I-beam the system is no longer conserved. All the kinetic energy is used to drive the I-beam down by distance s23. We will apply work energy principle on the system:

Wnet = ( P_3 - P_1 ) + W_friction

Wnet = m*g*s13 + F*s23

n*s23 = m*g*s13 + F*s23

Where, n: average force the hammerhead exerts on the I-beam.

s13 = s12 + s23

Hence,

n = m*g*( s12/s23 + 1) + F

n = 200*9.81*(3/0.074 + 1) + 60

n = 81562 N

6 0

3 years ago

Puck B has twice the mass of puck A. Starting from rest, both pucks are pulled the same distance across frictionless ice by stri

gogolik [260]

Answer:

(a) 1 : 2

(b) same

Explanation:

Let the mass of puck A is m and the mass of puck B is 2 m.

initial speed for both the pucks is same as u and the distance is same for both is s.

let the tension is T for same.

The kinetic energy is given by

$K = 0.5 mv^2$

(a) As the speed is same, so the kinetic energy depends on the mass.

So, kinetic energy of A : Kinetic energy of B = m : 2m = 1 : 2

(b) A the distance s same so the final velocities are also same.

8 0

2 years ago

The influence of likes and dislikes on thinking called?

jenyasd209 [6]

'A biased oppinion'
When you like something and right a report on it your opinion will come through about that subject, the same thing occurs if you dislike something.
:) Hope this helps x

3 0

3 years ago

How to live a life like scientists​

How to live a life like scientists