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SVEN [57.7K]
2 years ago
14

What best defines an extensive property of a substance? (4 points) A property that is observable A property that is measurable A

physical property that depends on the sample size A physical property that is not dependent on sample size
Chemistry
1 answer:
kolbaska11 [484]2 years ago
6 0

Answer:

A physical property that depends on the sample size 

Explanation:

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Please help will mark brainlyist
Tema [17]

Answer:

Answer choice B

Explanation:

6Li + Ga₂S₃ => 3Li₂S + 2Ga

Given: 0.90 mole Ga Formed

Question: How many moles Li were used

Note => From the balanced equation note that 6 moles Li are required to produce 2 moles Ga. So, when mole ratios are applied, the value for moles of Lithium will be greater than the given value for the Ga yield. To take advantage of this idea stoichimetrically, use a ratio of the coefficients of Li and Ga as a multiple of the given to get a greater number of moles Li.

That is, use 6/2 x 0.90 mole => 2.7 moles Li used.

(Note: one would NOT want to use 2/6 x moles Ga b/c a number smaller than 0.9mole would be used.)

What I'm trying to share with you in this problem makes mole-mole problems very straight forward. When working chemical stoichiometry problems learn to use this rule => Convert all data to moles, apply mole ratio  of given and unknown in the balanced equation to increase or decrease magnitude of the needed answer value.

Example

Given:      N₂      +              3H₂                      => 2NH₃

           5moles      ?moles H₂ are required

moles of H₂ required = 3/1(5) moles are required = 15moles H₂

Note, the ratio of coefficients chose to multiply times given moles is 3/1 because the value of H₂ must be larger than 5 moles b/c coefficient for H₂ is larger than coefficient for N₂. If 1/3 was chosen times the given 5 moles N₂ then the math gives 1/3(5) = 1.67 mole which is incorrect as it must be greater than 5 and the coefficients in the standard equation shows H₂ larger than N₂.

Using the 15 moles H₂ as the known reagent, how many moles NH₃ would be formed:

Note: In the balanced equation the coefficient for NH₃ is smaller than the coefficient for H₂. So, the answer must be smaller than 15; so use the mole coefficient ratio of 2/3 x known => a value smaller than the known and the correct answer. That is ...

moles NH₃ produced from 15 moles H₂ = 2/3(15) moles NH₃ formed = 10 moles NH₃ produced.

Note the moles NH₃ produced ( = 10 moles) is smaller than the given 15 moles of H₂ used.

7 0
2 years ago
Please help me understand how to...
KonstantinChe [14]

Answer:

m_{Cr_2O_3}^{actual}=62.4gCr_2O_3

Explanation:

Hello!

In this case, according to the reaction:

4Cr+3O_2\rightarrow 2Cr_2O_3

We can see there is a 4:2 mole ratio between chromium and chromium (III) oxide, this, for the given 56.2 g of chromium, the theoretical yield of the oxide product is computed down below:

m_{Cr_2O_3}^{theoretical}=56.2gCr*\frac{1molCr}{52.0gCr}*\frac{2molCr_2O_3}{4molCr} *\frac{151.99gCr_2O_3}{1molCr_2O_3}  =82.13gCr_2O_3

Now, considering the 76.0-% yield for this reaction, the actual yield turns out:

m_{Cr_2O_3}^{actual}=82.13gCr_2O_3*\frac{76.0gCr_2O_3}{100gCr_2O_3} \\\\m_{Cr_2O_3}^{actual}=62.4gCr_2O_3

Best regards!

3 0
3 years ago
Use Hess's Law to determine the enthalpy change (∆H) for the reaction: ClF + F2 → ClF3 Given: 2ClF + O2 → Cl2O + F2O. ∆H=167.4kJ
emmasim [6.3K]

Answer:

The enthalpy change (∆H) for the reaction is -108.7 kJ

Explanation:

Hess's law can be stated as: when the reactants are converted to products, the enthalpy change is the same, regardless of whether the reaction is carried out in one step or in a series of steps. Then, Hess's Law states that the enthalpy of one reaction can be achieved by algebraically adding the enthalpies of other reactions.

So,  to calculate the ∆H (heat of reaction) of the combustion reaction, that is, the heat that accompanies the entire reaction, you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient ( number of molecules of each compound participating in the reaction) and finally subtract them.

Enthalpy of combustion = ΔH = ∑Hproducts - ∑Hreactants

2 ClF + O₂ → Cl₂O + F₂O ∆H=167.4kJ

Cl₂O + 3 F₂O → 2 ClF₃ + 2 O₂ ∆H= -341.4kJ  

The previous equation must be inverted, and the enthalpy value is also inverted, that is, the sign is changed.

2 F₂ + O₂ →2 F₂O ∆H=-43.4kJ

Reactants and products are added or canceled, taking into account that certain substances sometimes appear as a reagent and others as a product, so they are totally eliminated (there is nothing left of them anywhere in the reaction, if the same amount in reagents and products) or partially (this substance remains, in less quantity, only on one side), obtaining:

2 ClF + 2 F₂ → 2 ClF₃

Then, as all the reactants and products have a stoichiometric coefficient of 2, dividend by that number is obtained:

ClF + F₂ → ClF₃

Adding the enthalpies algebraically, and dividing by 2, because to get the "data" reaction you had to multiply by two, you get:

ΔH= [167.4 kJ - 341.4 kJ - 43.3 kJ]÷2

ΔH= -108.7 kJ

<u><em>The enthalpy change (∆H) for the reaction is -108.7 kJ</em></u>

3 0
3 years ago
Be sure to answer all parts. Determine the electron-group arrangement, molecular shape, and ideal bond angle for the following m
choli [55]

Answer:

trigonal planar

Explanation:

The molecule SO3 is of the type AX3. The molecule is symmetrical and non polar.

There are three regions of electron density in the molecule. This corresponds to a trigonal planar geometry. This means that the three oxygen atoms are arranged at the corners of a triangle.  The bond angle is 120 degrees.

7 0
2 years ago
Which contains elements with similar properties in the periodic table? A.) a period B.) a column C.) a row
zysi [14]

b............................................

3 0
3 years ago
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