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2 years ago

14

What best defines an extensive property of a substance? (4 points) A property that is observable A property that is measurable A

physical property that depends on the sample size A physical property that is not dependent on sample size

1 answer:

kolbaska11 [484]2 years ago

6 0

Answer:

A physical property that depends on the sample size

Explanation:

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How objects with different masses and volumes have the same density?

AURORKA [14]

Answer:

mass and volume are independent. Two objects with the same volume can have different masses hence they can have different densities

Explanation:

The mass of atoms their size and how they are arranged determine the density

6 0

3 years ago

The standard Gibbs energy of reaction, ÄG°, for the dissociation of phenol is 56.4 kJ mol-1 at 298 K. Calculate the pKa of pheno

Neporo4naja [7]

Answer:

a.

9.88

Explanation:

ΔG = - 2.303 RT log Ka

ΔG is change in free energy at temperature T , Ka is equilibrium constant

- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa

- log Ka = 9.88 .

pKa = 9.88 .

4 0

3 years ago

The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

<u>The photodissociation of ozone by UV light is given by:</u>

O₃ + hν → O₂ + O (1)

<u>The first-order reaction of the equation (1) is:</u>

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>

<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

4 years ago

3. A 240 mL sample of argon gas at 270 K is cooled until the volume is 180 mL. What is the new temperature?

Alexeev081 [22]

Answer:

202.5 K

Explanation:

5 0

3 years ago

For this question, use the main assumptions of the Kinetic Molecular Theory of gases:

maksim [4K]

I would think that it's A

5 0

3 years ago

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