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SashulF [63]
3 years ago
10

2. Show the molecular formula and electron structure of the simplest compound that forms with only carbon and hydrogen atoms. (1

point) ​
Chemistry
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

CH3CH2CH2CH2CH2CH2OH-HEXAN-1-OL

Explanation:

hope this helps! plz mark as brainliest! :)

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Phosphorus crystallizes in several different forms, one of which is a simple cube with an edge length of 238 pm. What is the den
algol13

<u>Answer:</u> The density of phosphorus is 3.81g/cm^3

<u>Explanation:</u>

To calculate the density of phosphorus, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell = 1  (CCP)

M = atomic mass of phosphorus = 31 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = 238pm=238\times 10^{-10}cm    (Conversion factor:  1cm=10^{10}pm  )

Putting values in above equation, we get:

\rho=\frac{1\times 31}{6.022\times 10^{23}\times (238\times 10^{-10})^3}\\\\\rho=3.81g/cm^3

Hence, the density of phosphorus is 3.81g/cm^3

6 0
3 years ago
Someone please help me with this
igor_vitrenko [27]

Answer:

I think A should be the answer because oxygen is the chemical change of carbon.

7 0
3 years ago
A motorcycle rider leans into the turns while going around the curves on a race track. Explain why the rider does this. A) The r
babunello [35]

I'm pretty sure the answer is D or A


7 0
3 years ago
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Consider stoichiometric combustion of gasoline and air. Assume a full tank of gasoline holds 50 L (approximately 13.2 gallons),
Inessa05 [86]

Answer:

520 kg

Explanation:

Let's consider the combustion of isooctane.

C₈H₁₈(l) + 12.5 O₂(g) → 8 CO₂(g) +  9 H₂O(l)

We can establish the following relations:

  • 1 mL of C₈H₁₈ has a mass of 0.690 g (ρ = 0.690 g/mL).
  • The molar mass of C₈H₁₈ is 114.22 g/mol.
  • The molar ratio of C₈H₁₈ to O₂ is 1:12.5.
  • The mole fraction of O₂ in air is 0.21.
  • The molar mass of air is 28.96 g/mol.

50 L of isooctane require the following mass of air.

50 \times 10^{3}mLC_{8}H_{18}.\frac{0.690gC_{8}H_{18}}{1mLC_{8}H_{18}} .\frac{1molC_{8}H_{18}}{114.22gC_{8}H_{18}} .\frac{12.5molO_{2}}{1molC_{8}H_{18}} .\frac{1molAir}{0.21molO_{2}} .\frac{28.96 \times 10^{-3}kgAir}{1molAir} =520kgAir

5 0
4 years ago
15 POINTS RIGHT NOW!!!!
Anettt [7]

Answer:

It is valid because his experiment had clear variables.

Explanation:

He had clear variables and did everyhting the same for both plants, even though he had calcium in one and not in the other, which gives him a true and good result.

5 0
3 years ago
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