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Likurg_2 [28]
1 year ago
12

The acceleration due to gravity is lower on the Moon than on Earth. Which of the following is true about the mass and weight of

an astronaut on the Moon's surface compared to Earth
Physics
1 answer:
Naya [18.7K]1 year ago
3 0

Mass is the same, weight is less

<h3>What is the Weight and mass on Moon ?</h3>

As we know that the mass of the object is the measurement of the quantity of the matter that is present in it

So here we can say that if the mass of the object is m then its total quantity of the matter that is present in it is given as

mass = (density) × (volume)

Now for the weight of the object is defined as the force of gravity due to planet

Fg = mg

so the weight of the object is depending on the acceleration due to gravity of the planet

As we know that the gravity of moon is smaller than the gravity of the earth so here weight on the moon will be smaller than the weight on the Earth

Learn more about Weight on Moon here:

brainly.com/question/4080619

#SPJ4

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What will the weather be like in your area and your friend’s area over the next 24 hours?
stealth61 [152]

Answer:

hot I checked already in my phone

6 0
3 years ago
Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is
Ronch [10]

Complete Question

A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.

If the acceleration of the projective is : a = c/s m/s​2

Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?

Answer:

The value of the constant is  c = 28853.78 \ m^2 /s^2

Explanation:

From the question we are told that

         The acceleration is  a =  \frac{c}{s}\   m/s^2

         The  initial position of the projectile is s= 1.5m

         The final position of the projectile is s_f =  3 \ m

          The velocity is  v = 200 \ m/s

     Generally  time  =  \frac{ds}{dv}

   and  acceleration is a =  \frac{v}{time }

so

            a = v  \frac{dv}{ds}

 =>        vdv  =  a ds

             vdv  = \frac{c}{s}  ds

integrating both sides

           \int\limits^a_b  vdv  = \int\limits^c_d \frac{c}{s}  ds

Now for the limit

          a =  200 m/s

             b = 0 m/s  

         c = s= 3 m

          d =s_f= 1.5 m

So we have  

           \int\limits^{200}_{0}  vdv  = \int\limits^{3}_{1.5} \frac{c}{s}  ds

              [\frac{v^2}{2} ] \left | 200} \atop {0}} \right.  = c [ln s]\left | 3} \atop {1.5}} \right.

            \frac{200^2}{2}  =  c ln[\frac{3}{1.5} ]

=>           c = \frac{20000}{0.69315}

              c = 28853.78 \ m^2 /s^2

     

5 0
2 years ago
Estimate the volume of a typical house (2050 feet squared in size and 10 feet tall) answer in units of meters squared
Aloiza [94]

Answer:

Volume = 6248.48 m^{3}

Explanation:

Given:

The area of the house A = 2050\ ft^{2}

The height of the house h=10\ ft

We need to find the volume of a typical house.

Solution:

We find the volume of the house by multiplying the area of the house and height of the house.

Volume = Area\times height

Volume = A\times h

Area and height of the house are known, so we substitute these value in above equation.

Volume = 2050\times 10

Volume = 20500\ ft^{3}

Now we convert the unit from feet to meter.

Divide the volume by 3.2808 for m^{3}

Volume = \frac{20500}{3.2808}

Volume = 6248.48\ m^{3}

Therefore, the volume of the house is 6248.48 m^{3}

8 0
3 years ago
If i want an thrilling job witch should i chose im stuck beetween,
MA_775_DIABLO [31]

Answer:

1. horse rider

Explanation:

5 0
3 years ago
Number of complete 90.9 MHz radio waves over a 1.50 km distance
zimovet [89]
You could answer this right away IF you knew the length of each wave, right ?

Well,  Wavelength = (speed) / (frequency).

Speed = 3 x 10⁸ m/s  (the speed of light)
and
Frequency = 90.9 x 10⁶ Hertz.

So the length of each wave is  3 x 10⁸ / 90.9 x 10⁶  meters.

To answer the question, see how many pieces you have to cut
that 1.5 km into, in order for each piece to be 1 wavelength. 
It'll be

(1,500 meters) divided by (3 x 10⁸ meters/sec) / (90.9 x 10⁶ Hz)

To divide by a fraction, flip the fraction and then multiply:

(1500 meters) times (90.9 x 10⁶ Hz)/(3 x 10⁸ meters/sec)

=   454.5
5 0
3 years ago
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