In an experiment performed in a space station, a force of 74 N causes an object to have an acceleration equal to 9 m/s2. What is
1 answer:
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Explanation:
Given that,
2 strings both vibrate at exactly 220 Hz. The frequency of sound wave depends on the tension in the strings.
The tension in one of them is then decreased sightly, then will decrese.
Beat frequency,
So, the new frequency of the string is 217 Hz. Hence, this is the required solution.
A) The car overtakes the truck after 7.56 s
B) Initial distance between car and truck: 37.1 m
C) Speed of the truck: 15.9 m/s, speed of the car: 25.7 m/s
D) See graph in attachment
Explanation:
A)
The truck starts from rest and has a constant acceleration, so its position at time t can be written as
where
d is the initial distance between the truck and the car (the truck starts some distance ahead of the car)
is the acceleration of the truck
The car position instead it is given by the equation
where
is the acceleration of the car
The car overtakes the truck when the truck has moved 60.0 m, so when
Therefore, solving the equation, we find the time t when this occurs:
B)
In order to find the initial distance between the car and the truck (d), we have to calculate first the distance covered by the car during these 7.56 s. It is given by:
This means that after 7.56 s, when the car reaches the truck, the car has covered 97.2 m while the truck has covered 60 m. However, their positions are now equal, so we can write:
And by solving the equation, we find the value of d, the initial distance between car and truck:
C)
In order to find the speed of each vehicle, we use the following suvat equation:
where
u is the initial velocity
a is the acceleration
t is the time
For the truck, we have:
u = 0
So its speed after t = 7.56 s is
For the car, we have
u = 0
So its speed after t = 7.56 s is
D)
Find the graph required in attachment.
On the x-axis, it is represented the time in seconds. On the y-axis, it is represented the position in meters.
Both curves are in the shape of a parabola since the motion of both vehicles is an accelerated motion.
The curve that starts at -37.1 m is the curve representing the car: in fact, the car starts behind the truck by 37.1 m. The curve that starts from x = 0, t= 0 is that of the truck.
The two curves meets when t = 7.56 s: at that time, the two vehicles have reached the same position, and we see that occurs when x = 60 m, which means that this happens when the truck has covered 60 meters.
Learn more about accelerated motion:
#LearnwithBrainly
The wavelength of the radio photon is 268 m.
Electromagnetic waves travel with the speed of 3×10⁸m/s in vacuum. The speed of a wave <em>c i</em>s related to its frequency<em> f</em> and wavelengthλ as follows:
Thus the wavelength is given by,
Substitute 3×10⁸m/s for <em>c</em> and 1120×10³Hz for <em>f</em>.
Thus the wavelength of the radio photon from an AM station is 268 m
The initial speed of the shot is 15.02 m/s.
The Shot put is released at a height y<em> </em>from the ground with a speed u. It is released at an angle θ to the horizontal. In a time t, the shot put travels a distance <em>R</em> horizontally.
Pl refer to the attached diagram.
Resolve the velocity u into horizontal and vertical components, u ₓ=ucosθ and uy=u sinθ. The horizontal component remains constant in the absence of air resistance, while the vertical component varies due to the action of the gravitational force.
Write an expression for R.
Therefore,
In the time t, the net displacement of the shotput is y in the downward direction.
Use the equation of motion,
Substitute the value of t from equation (1).
Substitute -2.10 m for y, 24.77 m for R and 38.0° for θ and solve for u.
The shot put was thrown with a speed 15.02 m/s.
