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never [62]
3 years ago
6

In an experiment performed in a space station, a force of 74 N causes an object to have an acceleration equal to 9 m/s2. What is

the object's mass?
Physics
1 answer:
Stells [14]3 years ago
7 0

Answer:

<h3>The answer is 8.2 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{74}{9}  \\  = 8.222222...

We have the final answer as

<h3>8.2 kg</h3>

Hope this helps you

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Charles' law explains which of these phenomena?
Luden [163]
I think the correct answer would be that Charles' law explains why <span>a balloon deflates when the air around it cools. Charles' law is a simplification of the ideal gas law. At constant pressure,  volume and temperature have a direct relationship. Hope this helps.</span>
5 0
3 years ago
Match the property of a sound wave to the correct definition. A. amplitude . B. frequency  . C. period . D. pitch  E. loudness 
Maru [420]

Amplitude: How dense the medium is in the compression part of the wave, and how empty the rarefied area is.

Frequency: The number of wavelengths that pass a position in 1 second.

loudness: The quality of the sound that is most closely linked to the amplitude of the sound wave.

Period: The amount of time that it takes one wavelength to pass by a position.

Pitch: The quality of the sound that is most closely linked to the frequency of the sound wave.

5 0
3 years ago
Read 2 more answers
A circular loop of wire of cross-sectional area 0.12 m2 consists of 200 turns, each carrying 0.50 A. It is placed in a magnetic
defon

Answer:

0.52 Nm

Explanation:

A = 0.12 m^2, N = 200, i = 0.5 A, B = 0.050 T

Angle between the plane of loop and magnetic field = 30 Degree

Angle between the normal of loop and the magnetic field = 90 - 30 = 60 degree

θ = 60°

Torque = N i A B Sinθ

Torque = 200 x 0.5 x 0.12 x 0.050 x Sin 60

Torque = 0.52 Nm

4 0
3 years ago
An 8.00 kg mass moving east at 15.4 m/s on a frictionless horizontal surface collides with a 10.0 kg object that is initially at
andrew-mc [135]

Answer:

9.3m/s

Explanation:

Based on the law of conservation of momentum

Sum of momentum before collision = sum of momentum after collision

m1u1 +m2u2 = m1v1+m2v2

m1 = 8kg

u1 = 15.4m/s

m2 = 10kg

u2 = 0m/s(at rest)

v1 = 3.9m/s

Required

v2.

Substitute

8(15.4)+10(0) = 8(3.9)+10v2

123.2=31.2+10v2

123.2-31.2 = 10v2

92 = 10v2

v2 = 92/10

v2 = 9.2m/s

Hence the velocity of the 10.0 kg object after the collision is 9.2m/s

6 0
3 years ago
How is the surface area of an average person is 2m^2 in the chapter pressure
11Alexandr11 [23.1K]

Answer:

We have to show surface area =2m^2,with few conditions that is by considering Force =200000\ N and Pressure =100000\ Pa to be respectively.

Explanation:

The atmospheric pressure is =10^{5}\ Pa on Earth's surface.

The magnitude of the force exerted on a person by the atmosphere is =2\times 10^{5}\N (or)\ 200kN\ (or)\ 20\ ton.

Now to calculate surface area we can find it from pressure=\frac{force}{area} and re-arranging it to.

area=\frac{force}{pressure}

So plugging the values,

Surface area =\frac{20000}{10000}=2\ m^{2}

Hence from the above calculations we can say that surface area is 2m^2.

So the surface area of an average person can be said to have 2m^2, using the concept of pressure and force.

3 0
3 years ago
Read 2 more answers
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