To solve this problem we will apply the concept related to the electric field. The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,
Here,
k = Coulomb's constant
V = Voltage
r = Distance
Replacing we have
Therefore the magnitude of the electric field is
Answer:
4.4 m/s
Explanation:
momentum is always conserved so we can use conversation of momentum to solve the question, also momentum is a vector quantity ( it has magnitude and direction) which is the product of the bodies mass and velocity.
conservation law of momentum relates by the formula below:
momentum before collision = momentum after collision
M1U1 + M2U2 = M1V1 + M2V2
in the case of this two, the formula becomes
M1U1 + M2U2 = V (M1 + M2) since she jumped into his arm
there masses are M1 = 75.6 kg M2 = 59 kg and their velocities are U1 = 3.7 m/s and U2 = 5.4 m/s, their common velocity after collision = V since their motion is backward the formula becomes
-M1U1 - M2U2 = V(M1 + M2)
substitute the values into the equations
(-75.6 × 3.7 ) + (- 59 × 5.4) = V ( 75.6 + 59)
- 598.32 = 134.6 V
divide both side by 134.6
V = - 598.32 / 134.6 = -4.445 m/s = -4.4 m/s to nearest tenth the negative means in the same backward direction
A. The potential energy is always the highest at the top and the kinetic energy is always the lowest at the top.
Answer:
Explanation:
The given differential equation is
and y(0) = 0, y(L) =0
where T and ρ are constants
The given rewrite as
auxiliary equation is
Solution of this de is
y(0)=0 ⇒ C₁ = 0
y(L) = 0 ⇒
we need non zero solution
⇒ C₂ ≠ 0 and
solution corresponding these values