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Stels [109]
3 years ago
9

What forces must be overcome for a substance to melt

Chemistry
1 answer:
olga_2 [115]3 years ago
5 0

Intermolecular forces.

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A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti
MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_3H_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL

Putting values in above equation, we get:

2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M

Thus the molarity of the malonic acid solution is 0.08335 M

5 0
3 years ago
Describe the basic particle from which all ements are made
maxonik [38]
The answer for this question is: Atoms
7 0
3 years ago
Read 2 more answers
When the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solu
olya-2409 [2.1K]

Answer: The unknown solution had the lower concentration

Explanation: concentration will always move from higher to lower region. If the concentration of the unknown solution has increased, it therefore means that the initial concentration of the unknown solution was low

7 0
3 years ago
Pls help name any of these compounds​
Eva8 [605]

Answer:

D. Propanol

Explanation:

C3H7OH the presence of alcohol functional group makes it propanol

3 0
2 years ago
What volume of 0.140 HCl is needed to neutralize 2.58 of Mg(OH)2<br> ? ...?
elena-s [515]
To make a first step you have to know the balanced form for neutralization formula: Mg(OH)2(aq)+2HCl(aq)--\ \textgreater \ 2H2O+Mg(aq)+Cl(aq)&#10;
According to this, you can <span>calculate what you are being asked :</span>0.0442molMg(OH)2(x)(2molHCl)/(1molMg(OH)2)=0.0885molHCl
Then we have : 0.140MHCl=0.140(mol/L)HCl
Hope everything is clear, here is the exact answer you need : V=(0.0885molHCl)/(0.140(mol/L)HCl)=0.632LHCl&#10;

8 0
2 years ago
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