1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kicyunya [14]
3 years ago
5

What decides if an atom will be a cation or an anion?

Chemistry
1 answer:
JulijaS [17]3 years ago
7 0

The loss or gain of electrons

Explanation:

The loss or gain of electrons determines if an atom will become a cation or anion.

A cation is a positively charge ion

An anion is a negatively charged ion.

In an atom, we have sub-atomic particles:

 Protons are the positively charged particles

 Electrons are negatively charged

  Neutrons carry no charges

Only electrons can be lost or gained in chemical processes that forms cations and anions.

When a neutral atom gains electron, it has more electrons than protons. This makes it negatively charged and we call it an anion.

When a neutral atom loses an electron, the number of protons is more. We call it a cation.

Learn more:

Cations brainly.com/question/4670413

#learnwithBrainly

You might be interested in
If the chemist mistakenly makes 250 mL of solution instead of the 200 mL, what molar concentration of sodium nitrate will the ch
Evgesh-ka [11]

Answer:

0.120M is the concentration of the solution

Explanation:

<em>Assuming the mass of sodium nitrate dissolved was 2.552g</em>

<em />

Molar concentration is an unit of concentration widely used in chemsitry defined as the moles of solute (In this case NaNO3) in 1L of solution.

To find this question we must find the moles of NaNO3 in 2.552g. With this mass and the volume (250mL = 0.250L) we can find molar concentration as follows:

<em>Moles NaNO3 -Molar mass: 84.99g/mol-</em>

2.552g * (1mol / 84.99g) = 0.0300 moles NaNO3

<em>Molar concentration:</em>

0.0300 moles NaNO3 / 0.250L =

<h3>0.120M is the concentration of the solution</h3>
7 0
3 years ago
Someone help1!1!1!1!!!!!
alisha [4.7K]
The question is cut off in the picture
7 0
3 years ago
What is the activation energy of this reaction? 10 kJ 25 kJ 30 kJ 35 kJ
Nostrana [21]

Answer:

25 kj

Explanation:

8 0
3 years ago
The car wit fastest acceleration is the tempest. it has an acceleration of 6.1 m/s. suppose the car accelerates from rest to a f
ziro4ka [17]

<u>Given:</u>

Initial velocity (v1) = 0 m/s

Final velocity (v2) = 30 m/s

Acceleration (a) = 6.1 m/s2

<u>To determine:</u>

The time (t) taken to reach the final speed

<u>Explanation:</u>

Use the relation:

Acceleration (a) = [final velocity(v2) - initial velocity (v1)]/time (t)

t = (v2-v1)/a = 30-0/6.1 = 4.92 s

Ans: Time taken is around 4.9 s

3 0
3 years ago
Convert 52 centigrams to grams.<br> 520 g<br> 0.52 g<br> 5,200 g<br> 5.2 g
PIT_PIT [208]
1 cent ---------->  0.01 g
52 cent ---------> g

g = 52 * 0.01

 answer  0.52 g

hope this helps!.

5 0
2 years ago
Other questions:
  • Which of the following statements is true? Oceanic crust is thicker than continental crust. Both oceanic and continental crust i
    10·1 answer
  • List the specific sources of non renewable energy used in 2006
    12·1 answer
  • Calculate the density of gold (in units of g/mL) if a 5.00 cm cube has a mass of 2.41kg
    6·2 answers
  • What type of matter is salt water?
    10·1 answer
  • 24. Scientists usually work<br> a in teams<br> b. alone<br> C. in labs<br> d. by committee
    15·1 answer
  • Iron(II) can be oxidized by an acidic K2Cr2O7 solution according to the net ionic equation: Cr2O72− + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe
    12·1 answer
  • What is the number of C moles in 1.20*10²⁴ atoms of C
    12·1 answer
  • BASIC CALCULATIONS IN SPECTROSCOPY
    11·1 answer
  • A mixture of 620 lbmol/h of 36 mol% benzene and the remainder toluene is separated continuously into two products. One product i
    10·1 answer
  • Where information about each element is located
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!