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anyanavicka [17]
3 years ago
15

Encontrar la distancia y desplazamiento de las dos trayectorias si se mueve el móvil Desde A hasta B

Physics
1 answer:
Lerok [7]3 years ago
6 0

Answer:

Build Your Confidence

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Explanation:

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A natural water molecule (H2O) in its vapor state has an electric dipole moment of magnitude, p = 6.2 x 10-30 C.m. (a) Find the
Vika [28.1K]

Answer:

a    D = 3.9 *10^{-12} \ m

b    \tau_{max} = 1.24 *10^{-25} \  N\cdot m

c   W =  2.48 *10^{-25} J

 

Explanation:

From the question we are told that

   The magnitude of electric dipole moment is  \sigma  =  6.2 *10^{-30} \ C \cdot m

     The electric field is E =  2*10^{4} \ N/C

   

The distance between the positive and negative charge center is mathematically evaluated as

     D =  \frac{\sigma }{10 e}

Where  e is the charge on one electron which has a constant value of  e = 1.60 *10^{-19} \ C

  Substituting values

     D =  \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}

      D = 3.9 *10^{-12} \ m

The maximum torque is mathematically represented as

       \tau_{max} = \sigma * E  * sin (\theta)

Here  \theta  =  90^o

This because at maximum the molecule is perpendicular to the field

    substituting values

       \tau_{max} =  6.2 *10^{-30} * 2*10^{4} sin ( 90)

       \tau_{max} = 1.24 *10^{-25} \  N\cdot m

The workdone is mathematically represented as

      W =  V_{(180)} - V_{0}

where   V_{(180)} is the potential energy at 180° which is mathematically evaluated as

     V_{(180) } = -   \sigma  * E  cos (180)

Where the negative signifies that it is acting against the  field

   substituting values

     V_{(180) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (180)

      V_{(180) } = 1.24*10^{-25} J

and

     V_{(0)} is the potential energy at 0° which is mathematically evaluated as

            V_{(0) } = -   \sigma  * E  cos (0)

   substituting values

     V_{(0) } = -   6.20 *10^{-30}  * 2.0 *10^{4}  cos (0)

      V_{(0) } =- 1.24*10^{-25} J

So W =  1.24 *10^{-25} - [-1.24 *10^{-25}]

    W =  2.48 *10^{-25} J

6 0
3 years ago
What is the strength of the electric field of a point charge of magnitude +4.8 × 10^-19 C at a distance of 4.0 × 10^-3 m? A. 3.6
soldi70 [24.7K]
Answer is D -  from the equation of electric field for point charge
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Why was the Roman empire able to prosper
gayaneshka [121]

Answer:

The mild climate enabled Romans to grow wheat, grapes, and olives. This abundance o food supported the people and allowed Rome to prosper. While the climate made year-long agriculture possible, Rome also had the advantage to be near water. The Tiber River helped the agricultural system to prosper

Explanation:

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3 years ago
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Please help soon!!!!
anyanavicka [17]
The Answer: Parallel
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A ball is thrown straight off a 150 meter high roof at 20 m/s.
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Answer:

I'll try and find the answer for you:)

Explanation:

I can't promise you I will though

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