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Lelechka [254]
3 years ago
9

How does a Freebody diagram tell you about the net force an object?

Physics
1 answer:
Sloan [31]3 years ago
6 0
So you subtract the numbers that are on the same axis. So if your gravitational force is 10 and your normal force is 5 you do 5-10 to get -5 since gravity acts downward
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Suggest values of the following in degree Celsius
ollegr [7]

Answer:

freezing water is 0°C

boiling water is 100°C

refrigerator 4°C

room is 20-22°C

3 0
2 years ago
You set a tuning fork into vibration at a frequency of 723 Hz and then drop it off the roof of the Physics building where the ac
zaharov [31]

Answer:

Explanation:

Given

Original Frequency f=723\ Hz

apparent Frequency f'=697\ Hz

There is change in frequency whenever source move relative to the observer.

From Doppler effect we can write as

f'=f\cdot \frac{v-v_o}{v+v_s}

where  

f'=apparent frequency  

v=velocity of sound in the given media

v_s=velocity of source

v_0=velocity of observer  

here v_0=0

697=723\cdot (\frac{343-0}{343+v_s})

v_s=(\frac{f}{f'}-1)v

v_s=(\frac{723}{697}-1)\cdot 343

v_s=12.79\approx 12.8\ m/s

i.e.fork acquired a velocity of 12.8 m/s

distance traveled by fork is given by

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v_s^2-0=2\times 9.8\times s

s=\frac{12.8^2}{2\times 9.8}

s=8.35\ m

                                       

5 0
3 years ago
If θ=0rad
wlad13 [49]

Answer:

π

Explanation:

ok that is the answer ok

4 0
2 years ago
Determine the magnitude of the force F1F1 component acting along the uu axis. Express your answer to three significant figures a
dybincka [34]

The first image below shows force F1 and the axes.

Answer: (F_{1})_{u}= 3.62 kN

Explanation: The second figure below express the parallelogram method to calculate the u component of force F1.

The <u>Parallelogram</u> <u>Method</u> is a method to determine resultant force and is applied as described in the question above.

With the three components, F_{1},(F_{1})_{u} and (F_{1})_{v} and angles, it can be used the <u>Law</u> <u>of</u> <u>Sines</u>, which states:

\frac{a}{sin\alpha} =\frac{b}{sin\beta} =\frac{c}{sin\theta}

i.e., there is a relation of proportionality between an angle and its opposite side.

For the triangle below:

\frac{u}{sin30} =\frac{F_{1}}{sin105}

u=F_{1}\frac{sin(30)}{sin(105)}

u=7\frac{0.5}{0.966}

u = 3.62

The magnitude of the component acting along the u-axis is 3.62kN.

5 0
3 years ago
I'm literally so dumb and about to fail my ap physics exam please help
Goshia [24]
Ok bro, so what’s the question lol
5 0
3 years ago
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