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Lelechka [254]
3 years ago
9

How does a Freebody diagram tell you about the net force an object?

Physics
1 answer:
Sloan [31]3 years ago
6 0
So you subtract the numbers that are on the same axis. So if your gravitational force is 10 and your normal force is 5 you do 5-10 to get -5 since gravity acts downward
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The following letter are used to help remember the characteristics of minerals:S I C C N. What does the S stand for?
Dennis_Churaev [7]

Your answer would be A. Solid. Hope this helps!

7 0
2 years ago
A force acts on a 5kg object at rest. How fast will the object accelerate on a frictionless surface?
MakcuM [25]

Answer: The answer is C.) 25 m/s^2.

Explanation: If you input 5 as s, you would have to use the exponent 2.  This means that you have to multiply 5 by 5.  5 x 5= 25.  

Edit: Also, because the surface is frictionless, it will make the object go faster too.  Nothing can really slow it down unless something blocks it.

8 0
2 years ago
Mia wanted to know how Earth’s movements created new landforms. She decided to read about folded mountains and their characteris
kifflom [539]

Answer:

I’m pretty sure it’s D

Explanation:

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5 0
3 years ago
Read 2 more answers
39. Draw a complete free body diagram of a 40 kg plastic crate at rest on a wooden table (us=0.7). The applied force to the righ
Leya [2.2K]

In order to draw the free body diagram, first let's calculate the friction force acting on the crate:

\begin{gathered} F_f=N\cdot\mu \\ F_f=40\cdot9.8\cdot0.7 \\ F_f=274.4\text{ N} \end{gathered}

Since the friction force is greater than the force applied, the crate will not move, and the friction force will be equal to the force applied.

The weight force is equal to 40 * 9.8 = 392 N.

So, drawing the diagram, we have:

4 0
1 year ago
Consider the equation . The dimensions of the variables v, x, and t are , , and , respectively. The numerical factor 3 is dimens
Vinvika [58]

Answer:

Part of the question is missing but here is the equation for the function;

Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.

Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3

Explanation:

What is applied is the principle of dimensional homogenuity

From the equation V = (1/3)zxt2.

  • V has  a dimension of [L/T]
  • x has a dimension of [L]
  • t has a dimension of [T]
  • from the equation, make z the subject of the relation
  • z = v/xt2 where 1/3 is treated as a constant
  • Substituting into the equation for z
  • z = L/T / L x T2
  • the dimension for z = 1/T3 i.e 1/ T - raised to power 3
5 0
3 years ago
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