Answer:
Option B
Explanation:
Magnification of Microscope is
Mo= Magnification of objective lens and
Me= magnification of the eyepiece.
Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.
Magnification,

when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.
Thus. Magnification will increase by decreasing the focal length.
The correct answer is Option B
Answer:
mass of the earth is directly proportional to its gravity and the radius is inversely proportional to its gravity. ... But when you go inside the surface of the earth inspiteof decreasing radius the force of gravity decreases.
Explanation:
Answer:
Homeostasis: When bacteria or viruses that can make you ill get into your body, your lymphatic system kicks in to help maintain homeostasis.
Metabolism: The processes of making and breaking down glucose molecules are example of metabolism.(respiration and photosynthesis)
Growth:The liver continues to form new cells to replace senescent and dying ones.
Hope these examples help you.
<span>The speed of longitudinal waves, S, in a thin rod = âšYoung modulus / density , where Y is in N/m^2.
So, S = âšYoung modulus/ density. Squaring both sides, we have, S^2 = Young Modulus/ density.
So, Young Modulus = S^2 * density; where S is the speed of the longitudinal wave.
Then Substiting into the eqn we have (5.1 *10^3)^2 * 2.7 * 10^3 = 26.01 * 10^6 * 2.7 *10^6 = 26.01 * 2.7 * 10^ (6+3) = 70.227 * 10 ^9</span>
Answer:

Explanation:
The two cars are under an uniform linear motion. So, the distance traveled by them is given by:

is the same for both cars when the second one catches up with the first. If we take as reference point the initial position of the second car, we have:

We have
. Thus, solving for t:
