Answer:
The angular acceleration is 11.66 rad/s²
Explanation:
Step 1: Given data
Three forces are applied to a solid cylinder of mass 12 kg
F1 = 15 N
F2 = 24 N
F3 = 19 N
R2 = 0.22m
R3 = 0.10m
Step 2: Find the magnitude of the angular acceleration
I = ½mr² = ½ * 12kg * (0.22m)² = 0.29 kg*m²
torque τ = I*α
τ = F2*R2 - F1*R1 = 24N*0.22m - 19N*0.10m = 3.38 N*m
This means
I = ½mr² = 0.29 kg*m²
τ = I*α = 3.38 N*m
OR
0.29 kg*m² * α = 3.38 N*m
α = 11.655 rad/s² ≈11.66 rad/s²
The angular acceleration is 11.66 rad/s²
Answer:
11.1 m/s
Explanation:
120 km = 120 x 1,000 = 120,000 m
3 hours = 3 x 60 x 60 = 3600 x 3 = 10,800 s
speed = 120,000 / 10,800
= 1200/108
= 11.1 m/s
Latent heat, energy absorbed or released by a substance during a change in its physical state (phase) that occurs without changing its temperature.
