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2 years ago

Explain how the extension of a spring is determined

Physics

1 answer:

fgiga [73]2 years ago

6 0

Answer:

For a given spring the extension is directly proportional to the force applied For example if the force is doubled, the extension doubles When an elastic object is stretched beyond its limit of proportionality the object does not return to its original length when the force is removed

Explanation:

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How are the amplitude and energy of a wave related

In-s [12.5K]

I would go with the last two because they are the same please give me brainiest if i am right

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2 years ago

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As players speed up, their kinetic energy will?

igomit [66]

Kinetic energy is proportional to the square of the speed. So when anything or anybody speeds up, its kinetic energy increases.

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3 years ago

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Two objects are dropped from different heights at the same instant. If the first object takes 10.7 seconds to hit the ground and

Lubov Fominskaja [6]

Answer:

The answer to your question is : 521.8 m

Explanation:

Data:

Different heights

Time first object (tfo) = 10.7 s

Time second object (tso)= 14.8 s

Initial speed of both objects(vo) = 0 m/s

a = 9.81 m/s²

Formula:

h = vot + 1/2 (a)(t)² but vo = 0 so, h = 1/2 (a)(t)²

Then, height fo h = 1/2 (9.81)(10.7)² = 561.6 m

height so h = 1/2(9,81)(14.8)² = 1074.4 m

Difference in their heights = 1074.4 m - 561.6 m = 521.8 m

5 0

3 years ago

A device for training astronauts and jet fighter pilots is designed to rotate the trainee in a horizontal circle of radius 11.0

kvv77 [185]

The velocity of the trainee is 29 m/s or 0.42 rev/s

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Centripetal Acceleration of circular motion could be calculated using following formula:

$\large {\boxed {a_s = v^2 / R} }$

<em>a = centripetal acceleration ( m/s² )</em>

<em>v = velocity ( m/s )</em>

<em>R = radius of circle ( m )</em>

Let us now tackle the problem!

<u>Given:</u>

Radius of horizontal circle = R = 11.0 m

Force Felt by the Trainee = F = 7.80w

<u>Unknown:</u>

Velocity of Rotation = v = ?

<u>Solution:</u>

$F = ma$

$F = m\frac{v^2}{R}$

$7.80w = m\frac{v^2}{R}$

$7.80mg = m\frac{v^2}{R}$

$7.80g = \frac{v^2}{R}$

$7.80 \times 9.8 = \frac{v^2}{11.0}$

$v^2 = 840.84$

$v \approx 29 ~m/s$

$\omega = \frac{v}{R}$ → in rad/s

$\omega = \frac{v}{2 \pi R}$ → in rev/s

$\omega = \frac{29}{2 \pi \times 11.0}$

$\omega \approx 0.42 ~ rev/s$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437

Kinetic Energy : brainly.com/question/692781

Acceleration : brainly.com/question/2283922

The Speed of Car : brainly.com/question/568302
Uniform Circular Motion : brainly.com/question/2562955
Trajectory Motion : brainly.com/question/8656387

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Circular Motion

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Circular , Ball , Centripetal

6 0

3 years ago

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An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200 rev/s . The magnitude

blagie [28]

Answer:

(A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

Explanation:

Given that,

Initial angular velocity = 0.200 rev/s

Angular acceleration = 0.883 rev/s²

Diameter = 0.760 m

Time = 0.204 s

(A). We need to calculate the angular velocity of fan

Using equation of angular motion

$\omega_{f}=\omega_{i}+\alpha t$

Put the value into the formula

$\omega_{f}=0.200+0.883\times0.204$

$\omega_{f}=0.380\ rev/s$

(B). We need to calculate the number of revolution

Using formula of angular displacement

$\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2$

Put the value into the formula

$\theta=0.200\times0.204+\dfrac{1}{2}\times0.883\times(0.204)^2$

$\theta=0.059\ rad$

(C). We need to calculate the tangential speed of the blade

Using formula of speed

$v=\dfrac{d}{2}\omega_{f}$

Put the value into the formula

$v=\dfrac{0.760}{2}\times0.380\times2\pi$

$v=0.907\ m/s$

(D). We need to calculate the tangential acceleration of the blade

Using formula of tangential acceleration

$a_{t}=\alpha r$

Put the value into the formula

$a_{t}=0.883\times0.38\times2\pi$

$a_{t}=2.10\ m/s^2$

Hence, (A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

3 0

3 years ago