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stiks02 [169]
2 years ago
5

a pulley is assumed massless and frictionless and rotates freely about its axle. the blocks have masses m1=40g and a block m2= 2

0g, and block m1 is pulled to the right by a horizontal force magnitude f=0.03n. find the magnitude of acceleration of a block m2 and the tension in the cord.....?
Physics
1 answer:
Assoli18 [71]2 years ago
6 0

The magnitude of acceleration of a block m₂ is 0.05 m/s² and the tension in the cord is 0.01 N.

Given:

mass of block 1, m₁ = 40 gm = 40×10⁻³ kg

mass of block 2, m₂ = 20 gm = 20×10⁻³ kg

Applied force, F = 0.03 N

Calculation:

Consider the free-body diagram of the system as shown below. Using Newton's second law of motion we get:

F = ma

where F is the applied force

            m is the total mass of the system

            a is the acceleration of block 2 (as it is pulled by horizontal force)

From the above equation we get:

0.03 N = (m₁+m₂) a

⇒ a = (0.03 N) / (m₁+m₂)

⇒ a = (0.03 N) / (40×10⁻³ kg + 20×10⁻³ kg)

⇒ a = 0.5 m/s²

Now, from the free-body diagram of block 2 as shown in figure 3, we get:

Balancing the forces along the horizontal:

∑Fₓ = 0

∴ T = m₂ a

where T is tension in the string

           a is the acceleration of block 2

Applying values in the above equation we get:

T = (20×10⁻³ kg) × (0.5 m/s²)

  = 0.01 N

Therefore, the acceleration of block 2 due to the applied horizontal force is 0.5 m/s² and the tension in the cord is 0.01 N.

Learn more about tension here:

<u>brainly.com/question/13397436</u>

#SPJ4

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Answer:

10s

Explanation:

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Her speed where constant

= 100/20

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It would take Alice

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It would take Alice 10s to run $50$ meters.

5 0
3 years ago
If a boat and its riders have a mass of 900 kg and the boat drifts in at 1.4 m/s how much work does sam do to stop it?
Rama09 [41]
The initial kinetic energy of the boat and its rider is
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After Sam stops it, the final kinetic energy of the boat+rider is
K_f = 0 J
because its final velocity is zero.

For the law of conservation of energy, the work done by Sam is the variation of kinetic energy of the system:
W=K_f-K_i =0-882 J=-882 J
where the negative sign is due to the fact that the force Sam is applying goes against the direction of motion of the boat.
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3 years ago
An 80-kilogram skier slides on waxed skis along a horizontal surface of snow at constant velocity while pushing with his poles.
ivann1987 [24]

Answer:

The force F is created by the reaction of the Earth to the thrust of the rods, whereby the thrust is created by a force of action and reaction.

Explanation:

To answer this question, let's write Newton's second law of the two axes

Y Axis  

        Fy + N - W = 0

        Fy + N = W

X axis

       Fx - fr = 0

      Fx = fr

The force F is created by the reaction of the Earth to the thrust of the rods, whereby the thrust is created by a force of action and reaction.

   The direction of this force is along the length of the rods that are in an Angle, where the x and y components of the force come from

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3 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.83 times a second. A tack is stuck in the tire a
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Answer:

The tangential speed of the tack is 6.988 meters per second.

Explanation:

The tangential speed experimented by the tack (v), measured in meters per second, is equal to the product of the angular speed of the wheel (\omega), measured in radians per second, and the distance of the tack respect to the rotation axis (R), measured in meters, length that coincides with the radius of the tire. First, we convert the angular speed of the wheel from revolutions per second to radians per second:

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v = \left(17.781\,\frac{rad}{s} \right)\cdot (0.393\,m)

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Answer:

attached below

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