By using the combined gas law which says that P1V1/T1 = P2V2/T2, assuming constant pressure, the volume at the required temperature can be obtained.((0.002 m3)(50+273.15))/(20+273.15) = volume 2 at 50 degrees C.
This gives the answer 0.0022048 m3
<span>René Descartes suggests this.</span>
Answer:
(h₁-h₂) = 2.30 10² m
Explanation:
The pressure depends on the height with the formula
P = P_atm + rho g h
Let's apply this expression for the building
P₁ = P_atm + rho_air g h₁
P₂ = P_atm + rho_air g h₂
Subtract
P₁ - P₂ = roh_air g (h₁ –h₂)
The measured pressure is in mm Hg to take this unit to units of pressure must be multiplied by the density of mercury and the acceleration of gravity
P₁- P₂ = rho_Hg g (h₁-h₂) _Hg
rho_Hg g (h₁-h₂) _Hg = roh_air g (h₁ –h₂)
(h₁ –h₂) = rho_Hg / rho_air (h₁-h₂) _ Hg
Let's calculate
(h₁-h₂) = 13600 / 1.18 (695-675)
(h₁-h₂) = 2.30 10⁵ mm
Let's reduce to meter
(h₁-h₂) = 2.30 10⁵ mm (1 m / 10³ mm)
(h₁-h₂) = 2.30 10² m