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3 years ago

How long does it take to reach the moon?

2 answers:

5 0

Over the past few decades man has always embarked on different space exploration by traveling to the moon. A typical Journey to the moon from Earth will take about 3 days in recent times.

It takes about 3 days for a spacecraft to reach the Moon. During that time a spacecraft travels at least 240,000 miles

In the year 1969 the first man (Neil Armstrong ) landed on the moon, the journey took him 8 days, 3 hours, 18 minutes, 35 seconds, on 16 July.

Research on space exploration is still growing and expanding, with large amount of funding and support globally.

Learn more about Space and moon exploration:

brainly.com/question/3983943

aev [14]3 years ago

5 0

Answer:

about 3 days

thanks

have a great day

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A pivoted beam supports a load P at one end and a load Q at the other end.

Alecsey [184]

Answer:

P Q

c) 30 10

Explanation:

3 0

3 years ago

You are in charge of a cannon that exerts a force 11500 N on a cannon ball while the ball is in the barrel of the cannon. The le

IRISSAK [1]

Answer:

m = 7.48 kg

Explanation:

force (f) = 11,500 N

length of barrel (s) = 1.7 m

angle above the ground = 49.3 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

initial velocity (u) = 0 m/s

final velocity (v) = 72.3 m/s

mass (m) = ?

force = mass (m) x acceleration (a)

acceleration (a) = force / mass (m)

acceleration (a) = 11500 / m

applying the equation of motion $v^{2} = u^{2} + 2as$ , we can get the mass

$72.3^{2} = 0^{2} + (2 x \frac{11500}{m} x 1.7 )$

5227.3 = 0 + $\frac{39100}{m}$

m = $\frac{39100}{5227.3}$

m = 7.48 kg

5 0

3 years ago

Plzz answer this question

Vera_Pavlovna [14]

Mass does not change anywhere in the space .
So the given 30N is equal to the product of mass of the body and the acceleration due to gravity at that place in space.
After finding the mass of the body multiply it by the given acceleration due to gravity.
Mg is the approximate force due to gravity between the mass and the planet.

I hope this may help you.

6 0

4 years ago

Consider the elementary gas-phase reversible reaction A 3C Pure A enters at a temperature of 400 K and a pressure of 10 atm. At

xxMikexx [17]

Answer:

Explanation:

The equilibrium equation is:

$A\rightleftharpoons 3C$

The initial concentration of A can be calculated from the ideal gas equation:

$pV=nRT\\\\n/v=p/(RT)\\\\C_A=\dfrac{10atm}{0.08206(atm-dm^3/K-mol)/times 400K}\\\\C_A=0.304mol/liter$

Determine the conversion of substance A to substance C using an ICE table and the Kc constant:

A ⇄ 3C

I 0.304 0

C - x + 3x

E 0.304 - x 3x

$K_c=0.25=\dfrac{(3x)^3}{(0.304-x)}$

Solve for x:

You need to use a graphing calculator:

108x³ = 0.304 - x

108x³ + x - 0.304 = 0

x ≈ 0.1195 mol/liter

Then:

$C_A=0.304mol/liter-0.1195mol/liter=0.1845mol/liter\\\\C_C=3\times 0.304mol/liter=0.912mol/liter$

The equilbrium conversion is:

$\% = [0.304mol/liter-0.1845mol/liter]/(0.304mol/liter)\times 100$

$\% \approx 39\%$

3 0

3 years ago

A control is a ____.

Nina [5.8K]

A control is B, standard for comparison. This is used to compare for example plants and using different fertilizers and then have one with no fertilizer. Controls are basically just a base to the entire experiment

I hope this helps you!:)

6 0

3 years ago