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Vedmedyk [2.9K]
2 years ago
11

How long does it take to reach the moon?

Physics
2 answers:
alexdok [17]2 years ago
5 0

Over the past few decades man has always embarked on different space exploration by traveling to the moon. A typical Journey to the moon from Earth will take about 3 days in recent times.

  • It takes about 3 days for a spacecraft to reach the Moon. During that time a spacecraft travels at least 240,000 miles

  • In the year 1969 the first man (Neil Armstrong ) landed on the moon, the journey took him 8 days, 3 hours, 18 minutes, 35 seconds, on 16 July.

Research on space exploration is still growing and expanding, with large amount of funding and support globally.

Learn more about Space and moon exploration:

brainly.com/question/3983943

aev [14]2 years ago
5 0

Answer:

about 3 days

thanks

have a great day

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Answer:

True, because tech is what creates thing like cars and other veicals (i know i spelled it wrong)

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Explanation:

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3 years ago
A 65-kg skier grips a moving rope that is powered by an engine and is pulled at a constant speed to the top of a 230 hill. The s
Sveta_85 [38]

Answer:

The required power by the engine is 33.0 hp

Explanation:

Solution

Newton's second law says that, the net force Fnet on an object of mass m will accelerates the object

Where

Fnet = ma

a = acceleration

θ = angle of incline,

m = mass of the 30 skiers,

f = frictional force

N = normal force

mg sinθ, mg cos θ are components of weight skier

F = the force applied by engine

Now,

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m = 30 (65kg) = 1950 kg

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Fnet, x=ma

Now,

F-mg sin θ - f = 0

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The kinetic frictional force is denoted by

f = μk N ------(2)

μk = The coefficient of the kinetic friction

We now, calculate the net force acting on the skiers along y axis

Fnet, y = ma

N- mg cos θ = 0

so,

N = mg cos θ

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f = μk mg cos θ

we substitute the value for equation (1)

F = mg sin θ + μk mg cos θ

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W = Fx

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so,

W = mg ( sinθ + μk cos θ)x

= (1950 kg) (9.81 m/s²) (sin 23° + (0.10) cos 23°) (320 m)

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Then,

The time from minute to s is converted

t =(2.0min) ( 60sec/1.0min) = 120 sec

Now we calculate the power needed by the engine to pull the skiers at the incline top

Thus,

P = W/t

we substitute  2.955 * 10 ^6 J for W and  120 s for t

we have,

P = 2.955 * 10 ^ 6 J/ 120 s

= ( 2.4625 * 10 ^ 4 W) (1.0 hp/746 W)

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