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Vedmedyk [2.9K]
2 years ago
11

How long does it take to reach the moon?

Physics
2 answers:
alexdok [17]2 years ago
5 0

Over the past few decades man has always embarked on different space exploration by traveling to the moon. A typical Journey to the moon from Earth will take about 3 days in recent times.

  • It takes about 3 days for a spacecraft to reach the Moon. During that time a spacecraft travels at least 240,000 miles

  • In the year 1969 the first man (Neil Armstrong ) landed on the moon, the journey took him 8 days, 3 hours, 18 minutes, 35 seconds, on 16 July.

Research on space exploration is still growing and expanding, with large amount of funding and support globally.

Learn more about Space and moon exploration:

brainly.com/question/3983943

aev [14]2 years ago
5 0

Answer:

about 3 days

thanks

have a great day

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rusak2 [61]

Answers:

a) T=7.04(10)^{-10} s

b) 5.11(10)^{12} cycles

c) 2.06(10)^{26} cycles

d) 46000 s

Explanation:

<h2>a) Time for one cycle of the radio wave</h2>

We know the maser radiowave has a frequency f of 1,420,405,751.786 cycles/s

In addition we know there is an inverse relation between frequency and time T:

f=\frac{1}{T} (1)

Isolating  T: T=\frac{1}{f} (2)

T=\frac{1}{1,420,405,751.786 cycles/s} (3)

T=7.04(10)^{-10} s (4) This is the time for 1 cycle

<h2>b) Cycles that occur in 1 h</h2>

If 1h=3600s and we already know the amount of cycles per second 1,420,405,751.786 cycles/s, then:

1,420,405,751.786 \frac{cycles}{s}(3600s)=5.11(10)^{12} cycles This is the number of cycles in an hour

<h2>c) How many cycles would have occurred during the age of the earth, which is estimated to be 4.6(10)^{9} years?</h2>

Firstly, we have to convert this from years to seconds:

4.6(10)^{9} years \frac{365 days}{1 year} \frac{24 h}{1 day} \frac{3600 s}{1 h}=1.45(10)^{17} s

Now we have to multiply this value for the frequency of the maser radiowave:

1,420,405,751.786 cycles/s (1.45(10)^{17} s)=2.06(10)^{26} cycles This is the number of cycles in the age of the Earth

<h2>d) By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth?</h2>

If we have 1 second out for every 100,000 years, then:

4.6(10)^{9} years \frac{1 s}{100,000 years}=46000 s

This means the maser would be 46000 s off after a time interval equal to the age of the earth

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Answer:

the answer is equal to 2.00v

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The hockey stick hits the puck forward. Give the reaction force
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I think the puck pushes the stick backwards

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On an ice skating rink, a girl of mass 50 kg stands stationary, face to face with a boy of mass 80 kg. The children push off of
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The velocity of the girl is  -4.8 m/s.

Using the principle of conservation of linear momentum, The total momentum of  bodies before and after collision is constant. Since the two objects are stationary, the initial momentum of each body is zero.

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0 = (80 × 3) + (50 × v)

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A motorcyclist heading east through a small town accelerate at constant 4.0meter per seconds square after he leaves the limits.
SVETLANKA909090 [29]

A) The position at t = 2.0 sec is 43.0 m east

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A)

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- The acceleration of the motorcyclist is constant and it is a=4.0 m/s^2

Since the motion is a uniformly accelerated motion, the position of the motorcylist is given by the expression

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where t is the time.

Substituting t = 2.0 s, we find the position:

x(2.0)=(5.0)+(15)(2.0)+\frac{1}{2}(4.0)(2.0)^2=43 m

B)

The velocity of the motoryclist can be found by calculating the derivative of the position. Therefore, it is:

v(t)=x'(t)=v_0 + at

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v_0=15.0 m/s is the initial velocity

a=4.0 m/s^2 is the acceleration

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v = 25 m/s

Solving the equation for t,

t=\frac{v-v_0}{a}=\frac{25-15}{4}=2.5 s

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3 years ago
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