A) 392 N/m
The spring constant can be found by applying Hooke's Law:
F = kx
where
F is the force applied to the spring
k is the spring constant
x is the stretching of the spring
Here we have:
F is the weight of the block hanging from the spring, which is
The stretching of the spring is
Therefore its spring constant is
B) 17.5 cm
Now that we know the value of the spring constant, we can calculate the new stretching of the spring when a mass of m=3.0 kg is applied to it. In this case, the force applied on the spring is
Therefore the stretching of the spring is
And since the natural length of the spring is 10 cm, the new length will be
L = 10 cm + 7.5 cm = 17.5 cm
C. course conditions
If the grass is grown then the golf ball will not be able to able to cover good ground distance
To be honest I don’t know
Augmentation or deduction of kinetic energy will tell you if any work is done here.
Explanation:
Here,
E<sub>k0</sub>=0.5mv<sub>0</sub><sup>2</sup>=16,537.5 J
E<sub>kf</sub>=0.5mv<sub>f</sub><sup>2</sup>=194,400 J
Now,
E<sub>k0</sub> - E<sub>kf</sub> = 177,862.5 J
Hence, work is done.
Have you understand, Shakira?
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