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likoan [24]
4 years ago
11

A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten

sity of the light at his location is 35.5kW/m2. He is wearing black clothing, so that the light incident on him is totally absorbed. What is the magnitude of the force the light beam exerts on the man? Do you think he could sense the force found in part (A)? a. The force is large enough to be felt by the man. b. The force the light beam exerts is much too small to be felt by the man.
Physics
1 answer:
babymother [125]4 years ago
8 0

Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

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A traveler pulls on a suitcase strap at an angle 36 above the horizontal with a force of friction of 8 N with the floor. If 752
goldenfox [79]

Answer:

71.8 N

Explanation:

T = Tension force in the strap

W = net work done = 752 J

f = force of friction = 8 N

d = displacement = 15 m

θ = angle between tension force and horizontal displacement = 36 deg

work done by frictional force is given as

W' = - f d

Work done by the tension force is given as

W'' = T d Cos36

Net work done is given as

W = W' + W''

W = T d Cos36 - f d

752 = T (15) Cos36 - (8) (15)

T = 71.8 N

8 0
3 years ago
Josie is running her first cross country meet. The race is a distance of 5 km and she has set a goal to finish the race in 21 mi
frutty [35]

Answer:

3.97 m/s

Explanation:

Speed is defined as the distance covered per unit time. Therefore, s=d÷t=d/t

Where d is distance and t is time

Given distance of 5 km and time of 21 minutes the speed would be given by dividing 5 km by 21 min. However, speed is expressed as km/h or m/s or miles per hour etc. So we nees to get our speed in one of these standard units.

Going for m/s

Conversion

1 km has 1000m hence

5 km=5*1000=5000m

1 min has 60 seconds hence

21 min=21*60=1260 s

Speed=5000m÷1260s=3.9682539682538 m/s

Rounded off, s=3.97 m/s

8 0
3 years ago
Which of the following is necessary for the greenhouse effect?
Mice21 [21]
It is the atmosphere

3 0
3 years ago
Five things that were invented by tesla?<br><br> please answer!!!!
algol13

Answer:

remote control, neon and fluorescent lights, wireless transmission, computers, smartphones

Explanation:

6 0
3 years ago
Read 2 more answers
A ball thrown vertically upward is caught by the thrower after 4.00 sec. Find the initial velocity of the ball and the maximum h
My name is Ann [436]

Answer:

Initial velocity = 39.2m/s

Maximum height is 78.4m

Explanation:

Given

Time, t = 4s

Solving (a): Initial Velocity

Using first law of motion:

v = u + at

Where

v = final\ velocity = 0

u = iniital\ velocity = ??

<em />a = acceleration = -g<em> [g represents acceleration due to gravity]</em>

t = 4

Substitute these value in the above formula:

v = u + at

0 = u - g * 4

0 = u - 9.8 * 4

Take g as 9.8m/s²

0 = u - 39.2

u = 39.2m/s\\

<em>Hence, initial velocity = 39.2m/s</em>

Solving (b): Maximum Height

This will be solved using second equation of motion

s = ut + \frac{1}{2}at^2

This becomes

s = ut - \frac{1}{2}gt^2

Substitute values for u, t and g

s = 39.2 * 4 - \frac{1}{2} * 9.8 * 4^2

s = 156.8 - 78.4

s = 78.4

<em>Hence, the maximum height is 78.4m</em>

7 0
4 years ago
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