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4 years ago

Use the picture to answer the question.

Physics

2 answers:

Vesnalui [34]4 years ago

6 0

Answer:

the bowling ball is red, it has three holes, and it is striped

Explanation:

iragen [17]4 years ago

5 0

Answer:

the bowling ball is round and red, smooth and hard also it has stripes and 3 finger wholes.

Explanation:

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A rock is thrown upward from the top of a 30 m building with a velocity of 5 m/s. Determine its velocity (a) When it falls back

Kobotan [32]

Answer:

a) 5 m/s

b) 17.8542 m/s

c) 24.7212 m/s

0.229

Explanation:

t = Time taken

u = Initial velocity = 5 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v=u+at\\\Rightarrow 0=5-9.81\times t\\\Rightarrow \frac{-5}{-9.81}=t\\\Rightarrow t=0.51 \s$

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=5\times 0.51+\frac{1}{2}\times -9.81\times 0.51^2\\\Rightarrow s=1.27\ m$

So, the stone would travel 1.27 m up

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.27+0^2}\\\Rightarrow v=5\ m/s$

Velocity as the rock passes through the original point is 5 m/s

$s=ut+\frac{1}{2}at^2\\\Rightarrow 1.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1.27\times 2}{9.81}}\\\Rightarrow t=0.51\ s$

Time taken to reach the original point is 0.51+0.51 = 1.02 seconds

So, total height of the rock would fall is 30+1.27 = 31.27 m

$s=ut+\frac{1}{2}at^2\\\Rightarrow 16.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{16.27\times 2}{9.81}}\\\Rightarrow t=1.82\ s$

Time taken by the stone to reach 15 m above the ground is 1.82+0.51 = 2.33 seconds

$v=u+at\\\Rightarrow v=0+9.81\times 1.82\\\Rightarrow v=17.8542\ m/s$

Speed of the ball at 15 m above the ground is 17.8542 m/s

$s=ut+\frac{1}{2}at^2\\\Rightarrow 31.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{31.27\times 2}{9.81}}\\\Rightarrow t=2.52\ s$

$v=u+at\\\Rightarrow v=0+9.81\times 2.52\\\Rightarrow v=24.7212\ m/s$

Speed of the stone just before it hits the street is 24.7212 m/s

F = Force

m = Mass = 100 kg

g = Acceleration due to gravity = 9.81 m/s²

s = Displacement = 4 km = 4000 m

P = Power = 1 hp = 745.7 Watt

t = Time taken = 20 minutes = 1200 seconds

μ = Coefficient of sliding friction

F = μ×m×g

⇒F = μ×100×9.81

W = Work done = F×s

P = Work done / Time

⇒P = F×s / t

$745.7=\frac{\mu \times 981\times 4000}{1200}\\\Rightarrow \mu=\frac{747.5\times 1200}{981\times 4000}\\\Rightarrow \mu=0.229$

Coefficient of sliding friction is 0.229

8 0

3 years ago

The mass of a cm3(cube) stone is 180.

ss7ja [257]

Density = (mass) / (volume), no matter how large or small the sample is.

We can't calculate the density, because you left out the number for the volume.
Also, you didn't tell us the unit for the mass of 180.

a). If the mass is 180 grams, then the density is

(180 gm) / (volume) .

b). No matter how many pieces you crush it into, and
no matter how large or small a piece is, its density is
the same. (I just wish we knew what the density really is.)

c). A piece may have 80 grams of mass. It doesn't "weigh" 80 grams.

Since the density of the whole rock is (180 gm) / (volume),
the density of any piece of it is (180 gm) / (volume).

Multiply each side by (volume): (Density) x (volume) = 180 gm

Divide each side by (density): Volume = (180 gm) / (density)

We can't calculate the volume of an 80-gm piece, because
we don't know the density. (That's because you left the volume
out of the question.)

4 0

3 years ago

2 pts

const2013 [10]

Answer:

I think the answer 1

Explanation:

im probably wrong too i dont know

5 0

3 years ago

A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec

Anit [1.1K]

Answer:

The charged particle will follow a circular path.

Explanation:

The magnetic force exerted on the charged particle due to the magnetic field is given by:

$F=qvB sin \theta$

where

q is the charge

v is the velocity of the particle

B is the magnetic field

$\theta$ is the angle between v and B

In this problem, the velocity is perpendicular to the magnetic field, so $\theta = 90^{\circ}, sin \theta=1$ and the force is simply

$F=qvB$

Moreover, the force is perpendicular to both B and v, according to the right-hand rule. Therefore, we have:

- a force that is always perpendicular to the velocity, v

- a force which is constant in magnitude (because the magnitude of v or B does not change)

--> this means that the force acts as a centripetal force, so it will keep the charged particle in a uniform circular motion. So, the correct answer is

The charged particle will follow a circular path.

8 0

4 years ago

¿cuales son los motivos para hacer una carta formal?<br>es para hoy porfavor necesito su ayuda

galina1969 [7]

La carta motivos es un documento escrito dentro del formato epistolar, por el cual se expresan las razones por la cual un postulante solicita algo, por ejemplo: continuar con sus estudios de posgrados en una universidad fuera de su ciudad natal o para dar una razón por la cual se encuentra calificado para un puesto de trabajo.

Nomas ponlo en tus palabras

8 0

3 years ago

Read 2 more answers