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kykrilka [37]
2 years ago
6

Write 20 physical Quantities withS.I unit and formula​

Physics
2 answers:
Svetach [21]2 years ago
7 0

Answer:

HERE IS YOUR ANSWER

Physical quantity => Unit

1)Length=>metre

2)Time=>second

3)Temperature=>Kelvin

4)mass=>kilogram

5)electric current=>ampere

6)luminous intensity=>candela

7)amount of substance=>mole

8)velocity=>m/s

9)acceleration=>m/s²

10)momentum=>kgm/s

11)density=>kg/m³

12)volume=>m³

13)force=>Newton(N)

14)Energy=>Joule(J)

15)Power=>Watt(W)

16)Pressure=>Pascal(Pa) or N/m²

17)Resistance=>ohm

18)Electrical potential=>volt(V)

19)plane angle=>radian

20)solid angle=>steradian

Explanation:

Ainat [17]2 years ago
6 0

<u>Physical</u><u> </u><u>quantity</u><u>:</u><u>-units</u>

  • Force, Weight:-Newton

  • Frequency:-Hertz.

  • Electric charge:-Coulomb

  • Electric potential (Voltage):-Volt.

  • Inductance:-Henry

  • .Capacitance:-Farad

  • Resistance, Impedance, Reactance:-Ohm

  • Electricalconductance:-Siemens.

  • Magneticflux:-Weber

  • Magnetic flux density:-Tesla.

  • Energy, Work, Hea:- Joule

  • Power, Radiant flux:-Watt

  • Angle:- Radian

  • Radioactivity :-Becquerel

  • Luminous flux:-leman
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A compact car has a mass of 1380 kg . Assume that the car has one spring on each wheel, that the springs are identical, and that
astraxan [27]

Answer:

A) k=34867.3384\ N.m^{-1}

B) \omega'\approx84\ Hz

Explanation:

Given:

mass of car, m=1380\ kg

A)

frequency of spring oscillation, f=1.6\ Hz

We knkow the formula for spring oscillation frequency:

\omega=2\pi.f

\Rightarrow \sqrt{\frac{k_{eq}}{m} } =2\pi.f

\sqrt{\frac{k_{eq}}{1380} } =2\times \pi\times 1.6

k_{eq}=139469.3537\ N.m^{-1}

Now as we know that the springs are in parallel and their stiffness constant gets added up in parallel.

<u>So, the stiffness of each spring is (as they are identical):</u>

k=\frac{k_{eq}}{4}

k=\frac{139469.3537}{4}

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B)

given that 4 passengers of mass 70 kg each are in the car, then the oscillation frequency:

\omega'=\sqrt{\frac{k_{eq}}{(m+70\times 4)} }

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Answer:

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Explanation:

The magnetic field inside a solenoid is given by the following formula:

B = \mu_{0}nI

where,

B = Magnetic Field Inside Solenoid

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n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

B_{1} = \mu_{0}n_{1}I  ------------------- equation 1

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n₂ = 6n₁

Therefore,

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Diving equation 1 and equation 2:

\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6

Hence, the correct option is:

<u>6</u>

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