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Bas_tet [7]
2 years ago
5

In what way did political policies act as a centrifugal force in the Soviet Union during the late 1980s

Chemistry
1 answer:
RUDIKE [14]2 years ago
6 0

The government gave the people more freedom to criticize the government which led to nationalist movements

<h3>What way did political policies act as a centrifugal force in the Soviet Union during the late 1980s ?</h3>

In the late 1980s, the economic and social situation in the Soviet Union was tense. The socialist economy was on the verge of collapse, the war in Afghanistan was an assured defeat, and the quality of life for Soviet citizens was appalling.

  • Due to these situations, the Soviet leader Mikhail Gorbachev decided to carry out a series of economic and political reforms, known as Perestroika and Glasnost, aimed at liberalizing the economy from a pure socialist model to a mixed model, and granting greater rights and civil liberties to the citizens.
  • This led to numerous mobilizations and demonstrations, which further weakened the already weak Soviet political apparatus and made possible the emergence of regionalist nationalisms in the former Soviet nations, especially those subjugated to the power of Russia.

Learn more about Soviet Union here:

brainly.com/question/1310325

#SPJ4

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PLEASE ANSWER QUICKLY!! LOTS OF POINTS!❤
Degger [83]

Explanation:

The idea here is that you need to use the Periodic Table of elements to find the mass number of the most common isotope of phosphorus, P.

5 0
3 years ago
80 POINTS!!! ALL PLATO USERS: asap!!!
Crank

This year course engages students in becoming skilled readers of prose written in a variety of periods, disciplines, and

rhetorical contexts and in becoming skilled writers who compose for a variety of purposes. More immediately, the course

prepares the students to perform satisfactorily on the A.P. Examination in Language and Composition given in the spring.

Both their writing and their reading should make students aware of the interactions among a writer’s purposes, audience

expectations, and subjects as well as the way generic conventions and the resources of language contribute to effectiveness

in writing. Students will learn and practice the expository, analytical, and argumentative writing that forms the basis of

academic and professional writing; they will learn to read complex texts with understanding and to write prose of

sufficient richness and complexity to communicate effectively with mature readers. Readings will be selected primarily,

but not exclusively, from American writers. Students who enroll in the class will take the AP examination.

4 0
3 years ago
Pulverized coal pellets, which may be approximated as carbon spheres of radius ro= 1 mm, are burned in a pure oxygen atmosphere
Ganezh [65]

Answer:

Explanation:

SO; If we assume that:

P should be the diffusion of oxygen towards the surface ; &

Q should be the  diffusion of carbondioxide away from the surface.

Then  the total molar flux of oxygen is illustrated by :

Na,x = - cD_{PQ}\frac{dy_P}{dr} +y_P(NP,x + N_Q,x)

where;

r is the radial distance from the center of the carbon particle.

Since ;

N_P,x = - N_Q, x ; we have:

Na,x = - cD_{PQ}\frac{dy_P}{dr}

The system is not steady state and the molar flux is not independent of r because the area of mass transfer 4\pi r^{2} is not a constant term.

Therefore,  using quasi steady state assumption, the mass transfer rate   4\pi r^{2}N_{P,x} is assumed to be independent of r at any instant of time.

W_{P}=4\pi r^{2}N_{P,x}

W_{P}=-4\pi r^{2}cD_{PQ}\frac{dy_{P}}{dr}        

       = constant

The oxygen concentration at the surface of the coal particle yP,R will be calculated from the reaction at the surface.

The mole fraction of oxygen at a location far from pellet is 1.

Thus, separating the variables and integrating result into  the following:

W_{P}\int_{R}^{\infty} \frac{dr}{r^{2}}=-4\pi

r^{2}cD_{PQ}\int_{y_{P,R}}^{y_{P,\infty }}dy_{P}

-W_{P}\frac{1}{r}\mid ^{\infty }_{R}= -4\pi cD_{PQ}(y_{P,\infty }-y_{P,R})

=> W_{P}= - 4\pi cD_{PQ}(1-y_{P,R})R

The mole of oxygen arrived at the carbon surface is equal to the mole of oxygen consumed by the chemical reaction.

W_{P} = 4 \pi R^2R"

W_{P}= 4\pi R^{2}k_{1}"C_{O_{2}}\mid _{R}

W_{P}= 4\pi R^{2}k_{1}"c y _{P,R}

-4\pi cD_{PQ}(1-y_{P,R})R= - 4\pi R^{2}k_{1}"c y _{P,R}

y_{P,R}=\frac{D_{PQ}}{D_{PQ}+Rk_{1}}

y_{P,R}=\frac{1.7 \times 10^{-4}}{1.7\times 10^{-4}+10^{-3}\times 0.1}

\mathbf{= 0.631}

Obtaining the total gas concentration from the ideal gas law; we have the following:

where;

R= 0.082m^3atm/kmolK

c=\frac{P}{RT} \\ \\ c=\frac{1}{0.082\times 1450} \\ \\ = 0.008405kmol/m^3

The steady state O_2 molar consumption rate is:

W_{P}= -4\pi cD_{PQ}(1-y_{P,R})R

W_{P}= -4\pi (0.008405)(1.7\times 10^{-4})(1-0.631)(10^{-3})

W_{P}= - 6.66\times 10^{-9}kmol/s

5 0
3 years ago
Determine the empirical and molecular formula for chrysotile asbestos. Chrysotile has the following percent composition: 28.03%
Mariulka [41]

The empirical and molecular formula : Mg₃Si₂H₂O₈ and Mg₆Si₄H₄O₁₆

<h3>Further explanation</h3>

Given

28.03% Mg, 21.60% Si, 1.16% H, and 49.21% O

Required

The empirical and molecular formula

Solution

Mol ratio : Mg : Si : H : O =

\tt \dfrac{28.03}{24}\div \dfrac{21.6}{28}\div \dfrac{1.16}{1}\div \dfrac{49.12}{16}\\\\1.17\div 0.771\div 1.16\div 3.07\\\\1.5\div 1\div 1.5\div 4\\\\3\div 2\div 2\div 8

So empirical formula :

\tt Mg_3Si_2H_2O_8

(Emprical formula)n=molecular formula

(Mg₃Si₂H₂O₈)n=520.8

(24.3+28.2+2.1+8.16)n=520.8

(258)n=520.8⇒n=2

The molecular formula : Mg₆Si₄H₄O₁₆

3 0
3 years ago
What happens to the body if the unirary system no longer functions?
MaRussiya [10]

Good morning,

I would say your answer is B).Toxic cellular waste builds up

The urinary system, also known as the renal system, produces, stores and eliminates urine, the fluid waste excreted by the kidneys. The kidneys make urine by filtering wastes and extra water from blood. Urine travels from the kidneys through two thin tubes called ureters and fills the bladder.

Hope this helps!

6 0
3 years ago
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