Answer:
Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.
Explanation:

Molarity of HCl solution = 0.1174 M
Volume of HCl solution = 83.15 mL = 0.08315 L
Moles of HCl = n



According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.
Then 0.009762 mol of HCl will recat with:

Moles of Sodium carbonate = 0.004881 mol
Volume of the sodium carbonate containing solution taken = 1L
Concentration of sodium carbonate in the solution before the addition of HCl:
![[Na_2CO_3]=\frac{0.004881 mol}{1 L}=0.004881 mol/L](https://tex.z-dn.net/?f=%5BNa_2CO_3%5D%3D%5Cfrac%7B0.004881%20mol%7D%7B1%20L%7D%3D0.004881%20mol%2FL)
Answer:
0.0140 M H₂C₆H₆O₆.
Explanation:
- We should mention the relation: <em>Ka = α²C,</em>
Where, Ka is the dissociation constant of the acid.
α is the degree of ionization of the acid.
C is the concentration if the acid.
<em>The percent of ionization (α %) = α x 100.</em>
α = √Ka/C
∴ α is inversely proportional to the concentration of the acid.
<em>So, the acid with the lowest concentration has the greatest percent ionization.</em>
Answer:
Explanation: "As a sample of matter is continually cooled, the average kinetic energy of its particles decreases. Eventually, one would expect the particles to stop moving completely. Absolute zero is the temperature at which the motion of particles theoretically ceases"
Answer:
Inflammation
Explanation:
Inflammation is the response to a cut. The blood vessels expand when you get cut to allow white blood cells to flock to the wound site. These attack any bacteria that got past the clot. If you mean <u>excess</u> bacteria, then that would be an infection.