1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zina [86]
1 year ago
12

The table shows columns that brenda uses for her notes on the properties of elements. her notes state that some elements can rea

ct to form basic compounds. a 3-column table with 2 rows. the first row has entries metals, metalloids, nonmetals. the second row has entries nothing, nothing, nothing. where should brenda place this property in her table? only in the column for metalloids only in the column for nonmetals in the columns for metalloids and for nonmetals in the columns for metals and for metalloids
Chemistry
1 answer:
AleksandrR [38]1 year ago
4 0

The element should be placed in the column for metalloids. Option A

<h3>What is the property of metals?</h3>

We know that the properties of metals can be used to identify an unknown substances as a metal. We know that metals are able to react with acids to liberate the metal salt and hydrogen gas. Metals do not react with bases because they can not accept electrons.

Metalloids are generally amphoteric in nature. They can react with both the acid and the basses to form compounds. The nonmetals do not react with acid or base.

Looking at the result, we are told that the entry in the second row have the entries  nothing, nothing, nothing. If this is the outcome, then it follows that the element should be placed in the column for metalloids.

Learn more about metalloids:brainly.com/question/2548493

#SPJ1

You might be interested in
A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper
Anit [1.1K]

Explanation:

Reaction equation for the given chemical reaction is as follows.

      2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}

Equation for reaction quotient is as follows.

         Q = \frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}

             = \frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}

             = 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of SO_{3} as equilibrium is achieved by using Q, is as follows.

  • This means that there are too much products.
  • Equilibrium will shift to the left towards reactants.
  • More SO_{3} is formed.
  • Partial pressure of SO_{3} increases.
4 0
3 years ago
The Electrical conductivity of an aqueous solution depends on the concentration of which particles in the solution
anyanavicka [17]
It depends on the concentration of ions which are responsible for the electrical conductivity in aqueous solutions.
6 0
3 years ago
Read 2 more answers
Which of the following is the best instrument to use to prepare a solution?
Semenov [28]
The answer to your question would be D Volumetric Flask 
5 0
3 years ago
Question 2<br> What is 3 x 108 written in standard form?
andriy [413]

I think you meant 3.08*10x^{8}

If you want to do that then you it will be 308 , 000 , 000

or if you meant 3 x 108 then it would literally just be 3 multiplied by 108 = 324

3 0
2 years ago
Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 40 mm Hg. Assume hemoglobin is 50%% sa
kumpel [21]

Answer:

The fractional saturation for hemoglobin is 0.86

Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Where Y_{O_{2} } \\ is the fractional oxygen saturation

{P_{O_{2} } is the partial pressure of oxygen

P_{50} is the partial pressure when 50% hemoglobin is saturated with oxygen

and h is the Hill coefficient

From the question,

{P_{O_{2} } = 40 mm Hg

P_{50} = 22 mm Hg

h = 3

Putting these values into the equation, we get

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3}  }

Y_{O_{2} } = \frac{64000 }{10648 + 64000  }

Y_{O_{2} } = \frac{64000 }{74648 }

Y_{O_{2} } = 0.86

Hence, the fractional saturation for hemoglobin is 0.86.

4 0
3 years ago
Other questions:
  • How are elements arranged in the Periodic Table?
    8·2 answers
  • you need 16.66ml (+-0.01) of 53.4 (+-0.4)wt% of NaOH with a density of 1.52 (+-0.01)g/mL to prepare 2.00L of 0.169M of NaOH. Wha
    8·1 answer
  • How does Elnora feel about her future? A) She takes one day at a time. B) She is apprehensive and anxious. C) She is optimistic
    10·1 answer
  • Please help<br>What is the possible ions of vanadium?
    10·1 answer
  • 34. According to Bohr's theory, an electron's path around the nucleus defines its
    10·1 answer
  • Determine the equilibrium vapor pressure of germanium metal at 508.0 C. The standard enthalpy of vaporization of germanium is 37
    9·1 answer
  • OHC-CH2-CH2-CH2-CHO<br><br> What is the IUPAC name of this compound ?
    14·1 answer
  • 4. Mineral used as fuel.
    10·2 answers
  • Give all possible, accurate, correct IUPAC names for the following compounds:
    9·1 answer
  • Please help!! <br><br> Is this an:<br><br> Acid<br><br> Base <br><br> Neither
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!