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patriot [66]
3 years ago
8

Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e.,

the product side is favored. If the species is an ion, include the word "ion" in the name. Use systematic names such as "methanol" instead of archaic names like "methyl alcohol" or "wood alcohol".)
(a) H3O+ (hydronium ion) + CH3O- (methoxide ion) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(b) CH3CH2O- (ethoxide ion) + HCl (hydrogen chloride) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(c) NH2- (amide ion) + CH3OH (methanol) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
Chemistry
1 answer:
DaniilM [7]3 years ago
3 0

Answer: a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

.

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Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of
Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

5 0
4 years ago
For many purposes we can treat methane as an ideal gas at temperatures above its boiling point of . Suppose the temperature of a
Elza [17]

Answer:

The volume decreases 5.5%

Explanation:

First, the question is incomplete, you are not giving the values of the temperatures and the pressure. However, I managed to find one similar question, and the given data is the temperature is lowered from 21 °C to -8°C, and the pressure decreased by 5%. If your data is different, you should only replace your data in the procedure, and you'll get an accurate result.

Now, with this data, let's see what we can do.

If this is an ideal gas, the equation to use is:

PV = nRT

Now, we know that this gas is suffering a decrease in temperature and pressure, but the moles stay the same so:

n₁ = n₂ = n

The constant R, is the same for both conditions. The only thing that differs here is the volume, temperature, and pressure. Therefore:

P₁V₁ = nRT₁   -----> n = P₁V₁ / RT₁

Doing the same with the pressure and volume 2 we have:

n = P₂V₂ / RT₂

Equalling both expressions and solving for V₂:

P₁V₁ / RT₁ = P₂V₂ / RT₂

V₂ = P₁T₂V₁ / P₂T₁

Now, as we know that P2 is 5% decreased from P1, so P2 = 0.95P1:

V₂ = P₁T₂V₁ / 0.95P₁T₁

The values of temperature in K:

T1 = 21+273 = 294 K

T2 = -8 + 273 = 265 K

Finally, let's calculate the volume:

V₂ = 264*P₁*V₁ / 294*0.95*P₁   ----> P cancels out  

V₂ = 264V₁ / 294*0.95

V₁ = 0.945V₂

With this, we can day that Volume 2 decreases.

Now the percentage change would be using the following expression:

%V = (V₁ - V₂ / V₁) * 100

Replacing the data we have:

%V = V1 - 0.945V₁ / V₁

%V = 0.055V₁ / V₁ * 100

%V = 5.5%

7 0
3 years ago
Identify which sets of quantum numbers are valid for an electron. Note that each set is ordered (n,l,ml,ms).
Fynjy0 [20]

Answer:

The answer to your question is:

Explanation:

Quantum numbers have the numbers

n = from 1 to 7

l = s = 0 p = 1 d = 2  f= 3

m = ± l

s = ±1/2

Group of answer choice.

A) 2, -1. 1, -1/2     The option is incorrect "l" could not be negative

B) 2, 1, 0 , 1/2       The option is posible

C) 3, 2, 1, -1          This option is incorrect "s" can not value -1

D) 4, 3, 2, 1/2       This option is correct

E) 4, 3, -4, 1/2      This option is incorrect "m2 can not value -4

F) 1, 1, 0, 1/2         This option is incorrect, the second number is not posible

G) 1, 1, 0, -1/2        This option is incorrect the second number could not be 1.

H) 3, 0, 0, 1/2       This option is incorrect "l" can not value 0

I) 0, 2, 0, 1/2         This option is incorrect, n can not value 0

J) 3, 2, 2, 1/2        This option is correct

K) 1, 2, 0, -1/2       This option is incorrect "l" can not value 2.

3 0
3 years ago
HELP PLEASE I BEG OF YOU
Vitek1552 [10]

Answer:

37.7%

Explanation:

58% of 65 is 37.7%

7 0
2 years ago
The Cabbage Indicator
Masja [62]

.A solution that serves as a pH indicator may be made using red cabbage, which is frequently available in homes. In essence, the color of the cabbage depends on the acidity of the solution and a pigment molecule called flavin or anthocyanin.

To determine whether a material is an acid or a base, red cabbage indicator is a purple-colored solution

Vinegar is an acid and its pH value is less than 7 and hence

Red color is produced

Baking soda is base and its pH value is greater than 7 and between 8-9  

and the color produced is sky blue

Bleach is the green which is also a basic and because the pH value is 10-11

Householder cleaner is having pH 11-13 which is basic and hence the yellow is the color of household cleaner .

A basic solution goes away from being basic and toward the center of the pH scale when an acid is introduced. The base is "neutralized" in this manner.

Learn more about pH value here

brainly.com/question/19584961

#SPJ10

3 0
2 years ago
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