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patriot [66]
2 years ago
8

Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e.,

the product side is favored. If the species is an ion, include the word "ion" in the name. Use systematic names such as "methanol" instead of archaic names like "methyl alcohol" or "wood alcohol".)
(a) H3O+ (hydronium ion) + CH3O- (methoxide ion) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(b) CH3CH2O- (ethoxide ion) + HCl (hydrogen chloride) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(c) NH2- (amide ion) + CH3OH (methanol) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
Chemistry
1 answer:
DaniilM [7]2 years ago
3 0

Answer: a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

.

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Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
viva [34]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

6 0
3 years ago
QUESTION 1 The ____________________ fan switch is nothing more than a thermostat that closes on a rise in temperature to start t
AVprozaik [17]

Answer:

temperature controlled

7 0
2 years ago
List emergency equipment, those are available in the laboratory?
mestny [16]

Answer:

Hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system and first aid kit.

Explanation:

Working in laboratories has many risks, therefore, preventive measures that should be incorporated to avoid the occurrence of any laboratory accidents.

Some of the important emergency equipment that should be available in laboratories are: hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system, chemical storage cabinet, first aid kits and fume hood.

Some of the personal protective equipment include lab coats, goggles, safety gloves and face shield.

7 0
2 years ago
Which compound type is formed when two atoms share two electrons?
Pie
Covalent compounds
All the best
5 0
2 years ago
Calculate the number of atoms
erastova [34]

Explanation:

13 are the number of atoms

4 0
3 years ago
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