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olga55 [171]
3 years ago
9

HELP!!! An experiment was conducted to determine if the intermolecular forces in two liquids affects their boiling points. Each

liquid was sprayed on a paper towel. Each
paper towel was wiped across a glass table to moisten the surface. The table shows a partial record of the experiment.
Experimental Record
Liquid Intermolecular Forces ?
А
relatively strong
B
relatively weak
What information should be recorded in the last column of the table?
Time taken by the liquids to start boiling
Time taken by the glass surface to dry
Volume of liquid required to moisten the paper towels
Time taken by the paper towels to become completely moist

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer: it would be b time taken by the glass surface to dry

Explanation:

i had took the test and i got it right

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A beaker containing 6.32 moles of PBr3, contains___
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Answer:

3.8 x 10²⁴molecules

Explanation:

Given parameters:

Number of moles  = 6.32moles

Unknown:

Number of molecules  = ?

Solution:

The number of moles can be used to derive the number of molecules found within a substance.

Now,

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Which organism would have the most variation in the DNA of its offspring?
Arada [10]

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Meiosis is a type of reductional cell division by which a parental cell produces 4 daughter cells (gametes), each containing half of the genetic material.

Animals (e.g., cats) generate gametes by meiosis which fuse during fertilization to produce new offspring.

Both amoeba and bacteria reproduce by a type of asexual reproduction called binary fission. Moreover, yeasts also reproduce asexually by a process called budding and fission.

Both asexual and sexual types of reproduction generate genetic variability by the emergence of new mutations in daughter cells.

Meiosis generates much more genetic variability than asexual types of reproduction due to two different processes:

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2 years ago
How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?
vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

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m = 65.8 g

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Tf = 36.9°C

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Q = mCΔT

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Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

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1 cal = 4.18 J

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3 years ago
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During chemical reactions, bonds are broken and new binds are formed.

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