To melt a solid, energy must be input into the solid to give the molecules high energy to disrupt the lattice bonds and change phase. To return the liquid to solid, the same amount of energy used in melting is required to be removed from the liquid, ideally. This is assuming there is no loss of energy in the process.
Atomic orbitals will fuse to new orbital that comes to be.
If you have 8.51x10-3 g of O₂, and excess ZnS, moles of ZnO form is 0.174×10⁻³ moles.
The balanced equation is given as :
2ZnS + 3O₂ ------> 2ZnO + 2SO₂
number of moles of O₂ = mass / molar mass
= 8.51 × 10⁻³ g / 31.998 g/mol
= 0.265× 10⁻³ moles
now, 3 moles of O₂ form 2 moles of ZnO
0.265× 10⁻³ moles of O₂ form( 2/3) × 0.265× 10⁻³ = 0.174×10⁻³ moles
The number of moles of ZnO is 0.174×10⁻³ moles
Thus, If you have 8.51x10-3 g of O₂, and excess ZnS, moles of ZnO form is 0.174×10⁻³ moles.
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0.2 m/s! keep in mind, speed= distance divided by time :D