Find the mechanical advantage of a ramp that is 6.0 m long and 1.5 m tall.

Physics

1 answer:

sveta [45]3 years ago

7 0

Answer: 4.0

Explanation:

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Two 4.0 kg masses are 1.0 m apart on a frictionless table. Each has 1.0 μC of charge.What is the magnitude of the electric force

xeze [42]

Coulomb's law:

Force = (8.99×10⁹ N m² / C²) · (charge₁) · (charge₂) / distance²

= (8.99×10⁹ N m² / C²) (1 x 10⁻⁶ C) (1 x 10⁻⁶ C) / (1.0 m)²

= (8.99×10⁹ x 1×10⁻¹² / 1.0) N

= 8.99×10⁻³ N

= 0.00899 N repelling.

Notice that there's a lot of information in the question that you don't need.
It's only there to distract you, confuse you, and see whether you know
what to ignore.

-- '4.0 kg masses'; don't need it.
 Mass has no effect on the electric force between them.

-- 'frictionless table'; don't need it.
 Friction has no effect on the force between them,
only on how they move in response to the force.

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A beam of monochromatic light with a wavelength of 400 nm in air travels into water. what is the wavelength of the light in wate

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The refractive index of water is $n=1.33$ . This means that the speed of the light in the water is:
$v= \frac{c}{n}= \frac{3 \cdot 10^8 m/s}{1.33 }=2.26 \cdot 10^8 m/s$

The relationship between frequency f and wavelength $\lambda$ of a wave is given by:
$\lambda= \frac{v}{f}$
where v is the speed of the wave in the medium. The frequency of the light does not change when it moves from one medium to the other one, so we can compute the ratio between the wavelength of the light in water $\lambda_w$ to that in air $\lambda$ as
$\frac{\lambda_w}{\lambda}= \frac{ \frac{v}{f} }{ \frac{c}{f} } = \frac{v}{c}$
where v is the speed of light in water and c is the speed of light in air. Re-arranging this formula and by using $\lambda=400 nm$ , we find
$\lambda_w = \lambda \frac{v}{c}=(400 nm) \frac{2.26 \cdot 10^8 m/s}{3 \cdot 10^8 m/s}=301 nm$
which is the wavelength of light in water.

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