A 1100-kg car pulls a boat on a trailer. (a) what total force resists the motion of the car, boat, and trailer, if the car exert
s a 1900-n force on the road and produces an acceleration of 0.550 m/s2 ? the mass of the boat plus trailer is 700 kg. (b) what is the force in the hitch between the car and the trailer if 80% of the resisting forces are experienced by the boat and trailer?
1 answer:
Refer to the diagram shown below.
R = total resistive force.
80% of this force is experienced by the boat and trailer.
T = the force in the hitch between the car and the trailer.
Overall motion:
Total mass = 1100 + 700 = 1800 kg
Acceleration = 0.55 m/s²
Driving force = 1900 N
Resisting force = R N
Therefore
(1900 - R N) = (1800 kg)*(0.55 m/s²)
1900 - R = 990
R = 910 N
0.2R = 182 N
0.8R = 728 N
Consider the motion of the car:
Driving force = 1900 N
Resistive force = 0.2R = 182 N
Force in the hitch = T NAcceleration = 0.55 m/s²
Mass = 1100 kg
Therefore
1900 - 0.2R - T = 1100*0.55
1900 - 182 -T = 605
T = 1113 N
Answer:
R = 910 N, the total resistive force.
T = 1113 N, the force in the hitch between the car and trailer.
R = total resistive force.
80% of this force is experienced by the boat and trailer.
T = the force in the hitch between the car and the trailer.
Overall motion:
Total mass = 1100 + 700 = 1800 kg
Acceleration = 0.55 m/s²
Driving force = 1900 N
Resisting force = R N
Therefore
(1900 - R N) = (1800 kg)*(0.55 m/s²)
1900 - R = 990
R = 910 N
0.2R = 182 N
0.8R = 728 N
Consider the motion of the car:
Driving force = 1900 N
Resistive force = 0.2R = 182 N
Force in the hitch = T NAcceleration = 0.55 m/s²
Mass = 1100 kg
Therefore
1900 - 0.2R - T = 1100*0.55
1900 - 182 -T = 605
T = 1113 N
Answer:
R = 910 N, the total resistive force.
T = 1113 N, the force in the hitch between the car and trailer.
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(a) The answer will be
(b) The answer will be
(c) The answer will be
Explanation :
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
The rule apply for the multiplication and division is :
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
The rule apply for the addition and subtraction is :
The least precise number present after the decimal point determines the number of significant figures in the answer.
(a) The sum of the measured values 521, 31.4, 0.85, and 9.0
In the given expression, 521 has 3 significant figures, 31.4 has 3 significant figures, 0.85 has 2 significant figures and 9.0 has 2 significant figures. From this we conclude that least precise number present after the decimal point is 0.
Thus, the answer will be
(b) The product 0.0052 × 386.2
In the given expression, 0.0052 has 2 significant figures and 386.2 has 4 significant figures. From this we conclude that 2 is the least significant figures in this problem. So, the answer should be in 2 significant figures.
Thus, the answer will be
(c) The product
The value of = 3.141414 =
is an irrational number.
In the given expression, 15.70 has 4 significant figures and has infinite significant figures. From this we conclude that 4 is the least significant figures in this problem. So, the answer should be in 4 significant figures.
Thus, the answer will be