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stich3 [128]
3 years ago
11

How many moles of nitric acid are present in 35.0 ml of a 2.20 M solution?

Chemistry
1 answer:
vodomira [7]3 years ago
8 0

Answer:

There are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

Explanation:

Molarity of the solution = 2.20 M

Molarity=\frac{number\:of\:moles}{Volume\:of\:Solution\:in\:L}\\\\Number\:of\:moles=Molarity\times(Volume\:of\:Solution\:in\:L)\\\\Volume\:of\:Solution=35\:mL=35\times10^{-3}L\\\\Number\:of\:moles=2.20\times35\times10^{-3}=77\times10^{-3}\:moles\:of\:HNO_{3}

Therefore, there are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

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An electron jumps from energy level 1 to energy level 2 by absorbing a photon of energy 8 eV. What is the most likely energy of
Mkey [24]

Answer:

C. 8 eV

Explanation:

In atoms, the energy of each level is quantised. That is one of the reasons why an electron can not exist between energy levels. Thus, when the electron absorbs energy of 8 ev, it get excited and jumps to energy level 2 which has the current value of energy of the electron.

Thus for the electron to move back to its initial energy level, it must emit the exact energy absorbed for its excitation. Therefore, the likely energy of the photon that will be emitted is 8 ev. This would make the electron to have energy that would make it to exist on energy level 1.

5 0
3 years ago
88 g of the strontium reacts with 160 g bromine to produce how many strontium bromide
aleksklad [387]

Mass of strontium = 88 g

Atomic mass of Sr = 87.62 u

Moles = mass /atomic mass

Moles of Sr =  88 / 87.62 = 1.004

Mass of bromine = 160 g

Atomic mass of Br = 79.904 u

Molar mass of Br₂ = 79.904 x 2 = 159.808 g/mol

Moles = mass /molar mass

Moles of Br₂ =  160 / 159.808 = 1.001

The balanced chemical equation of the reaction between strontium and bromine:

Sr(s) + Br₂(l) = SrBr₂

The molar ratio between Br₂  and SrBr₂ is 1:1

So the moles of SrBr₂ produced from 1.001 moles of Br₂ is 1.001.

Moles = mass /molar mass

Mass = moles x molar mass

Molar mass of SrBr₂ = 247.4280 g/mol

Mass = 1.001 mol x 247.4280 g/mol

Mass = 247.428 g

The mass of strontium bromide produced is 247.428 g.

6 0
3 years ago
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alexgriva [62]
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3 years ago
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Cloud [144]

Answer:

the yellow one

Explanation:

it includes direction

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3 years ago
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