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stich3 [128]
3 years ago
11

How many moles of nitric acid are present in 35.0 ml of a 2.20 M solution?

Chemistry
1 answer:
vodomira [7]3 years ago
8 0

Answer:

There are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

Explanation:

Molarity of the solution = 2.20 M

Molarity=\frac{number\:of\:moles}{Volume\:of\:Solution\:in\:L}\\\\Number\:of\:moles=Molarity\times(Volume\:of\:Solution\:in\:L)\\\\Volume\:of\:Solution=35\:mL=35\times10^{-3}L\\\\Number\:of\:moles=2.20\times35\times10^{-3}=77\times10^{-3}\:moles\:of\:HNO_{3}

Therefore, there are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

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1) The question contains an unknown unit


The number 8908.8 has to be in units of mass: for example, kg or grams.


Here you indicated L.


I am going to work assuming that L is a mass unit. So you can see the way to solve the problem, but you have to verifiy the real unit of the statement and substitute with it.



With that in mind you can find the density of the liquid from:


density  = mass / volume


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The volume of the vessel is calculated from the formula of volume for a rectantular prism.


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A compound accepts electrons from another substance to form a covalent bond. Which term best describes this compound’s behavior?
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<h3>What are the most common acid-base theories?</h3>
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A compound accepts electrons from another substance to form a covalent bond. The compound acts as a Lewis base.

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Every year, more than two million tons of citric acid are produced. It is frequently used as a flavoring, an acidifier, and a chelating agent.

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