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Anna71 [15]
3 years ago
11

Factor 125x3 + 343y3

Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

(5x + 7y)(25x² - 35xy + 49y²)

Step-by-step explanation:

125x³ + 343y³ ← is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b² )

125x³ = (5x)³ ⇒ a = 5x

343y³ = (7y)³ ⇒ b = 7y

125x³ + 343y³

= (5x + 7y)((5x)² - (5x × 7y) + (7y)²)

= (5x + 7y)(25x² - 35xy + 49y²) ← in factored form

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A dealer dealt the following cards from a shuffled deck: 3 , 2 , 2 , A , K , Q , K , 5 , 2 , 6 4 , 5 , K , 2 , 7 , 6 , A , J , J
zvonat [6]

Answer:

Total number of cards in shuffled deck=3 , 2 , 2 , A , K , Q , K , 5 , 2 , 6, 4 , 5 , K , 2 , 7 , 6 , A , J , J , A .

Total number of cards in a deck of card = 52 cards, out of which 26 are black cards and 26 are red card.

As, it is not given that out of the 20 cards dealt by dealer is either red card or black card.

A=3=2B +1 R or 1 B + 2 R

2=4=2 R +2 B

3=1=1 R or 1 B

4=1=1R or 1 B

5=2=2 R or 2 B

6=2=2 R or 2 B

7=1=1 R or 1 B

8=0

9=0

10=0

J=2= 2 R or 2 B

K=3= 2 R + 1 B or 1 R +2 B

Q=1=1 R or 1 B

If you count total number of black cards among the number of cards dealt by dealer, the possibilities of black card drawn is either 15 or 16 from 20 cards drawn.

As, Experimental probability is the probability obtained through experiment which is different from theoretical Probability.

Total number of cards =52

So, Probability of dealing with black cards by dealer which is either 15 or 16 in number is given by

=\frac{\text{total favorable outcome}}{\text{total possible outcome}}\\\\\frac{15}{52} {\text{or}} \frac{16}{52}=\frac{4}{13}.

6 0
4 years ago
Read 2 more answers
Please help me with the question please ASAP ASAP please please I’ll make as a brnlist
Neporo4naja [7]

Angle 1 - 72 degrees

Angle 2 - 36 degrees

Angle 3 - 16 degrees

Angle 4 - 144 degrees

<em><u>I hope this helps! :) </u></em>

5 0
3 years ago
Hank has 50 peso, 200 peso and 500 peso bills in his wallet. He has five less 200 bills as 50 bills, and half as many 500 bills
Varvara68 [4.7K]

For an amount of 6250 Peso, Hank have the quantities of the following denominations: 2503 bills of 50 peso, 2498 bills of 200 peso and 1249 bills of 500 peso.

<h3>How to apply systems of linear equations in real life equations</h3>

In this question we must translate the statement of the problem into mathematical expressions and then we must solve the resulting system. We need three equations that describe the quantities of 50 peso, 200 peso and 500 peso bills:

<em>y = x - 5</em>     (1)

<em>0.5 · y =</em> <em>z</em>    (2)

<em>x + y + z = 6250</em>     (3)

The solution of the system of <em>linear</em> equations is described below:

<em>x =</em> 2503, <em>y =</em> 2498, <em>z =</em> 1249

For an amount of 6250 Peso, Hank have the quantities of the following denominations: 2503 bills of 50 peso, 2498 bills of 200 peso and 1249 bills of 500 peso. \blacksquare

To learn more on systems of linear equations, we kindly invite to check this verified question: brainly.com/question/20379472

8 0
2 years ago
Find the domain of the function algebraically:<br><br> <img src="https://tex.z-dn.net/?f=R%28x%29%3D%5Cfrac%7Bx%7D%7Bx%5E%7B2%7D
BigorU [14]

The domain of the function is all real numbers except 2 and -1

Step-by-step explanation:

Domain is the set of inputs of a function on which the function is defined.

Given function is:

R(x) = \frac{x}{x^2-x-2}

In case of a function involving fraction, the function is undefined if the denominator is zero so in order to find the domain of the function algebraically , we have to find the values on which the function will be undefined

x^2-x-2 = 0\\x^2-2x+x-2 = 0\\x(x-2)+1(x-2) = 0\\(x+1)(x-2) = 0\\x+1 = 0 => x=-1\\x-2=0 = > x=2

The function will be undefined on x=-1 and x=2

So,

The domain of the function is all real numbers except 2 and -1

Keywords: Domain, functions

Learn more about domain and functions at:

  • brainly.com/question/2150928
  • brainly.com/question/2154850

#LearnwithBrainly

7 0
4 years ago
X+y=3<br> y+x= 5<br><br> help please
Oksana_A [137]
Solve by elimination ie eliminate x or y from the equations by performing operations on them.
first label the equations , to follow the process.
x - y = 5 ----------------(1)
x+ y = 3 ----------------(2)
If (1) and (2) are added then y will be eliminated.
(1) + (2) gives : 2x = 8 → x = 4
now substitute this value of x into either of the 2 equations and solve for y.
let x = 4 in (1) : 4 - y = 5 → -y = 1 → y = -1
check in (1) : 4-(-1) = 4+1 = 5
check in(2) : 4 - 1 = 3


So your answer is x = 4 , y = -1
8 0
3 years ago
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