All categories

3 years ago

you have a 4x6 photo of you and your friend. You order a 5x7 print of the photo. Is the new photo similar to the original?

2 answers:

7 0

Math wise no. 5×7 is a bigger form than 4×6, think of it like this, 4 squares up, and 6 squares side, same with the 5x7, its a bigger area and perimeter

beks73 [17]3 years ago

5 0

No because 4 times 6 =24 and 5 times 7 =35

You might be interested in

When a volcano erupts, the height of the peak is reduced and the upper portion is removed. The height of a volcano after it eru

ANTONII [103]

Answer:

9670 feet

Step-by-step explanation:

The height given (8219.5 ft) is 85% OF ORIGINAL, hence original is much higher. But how do we figure this out?

we translate word problem to equation.

8219.5 IS 85% of TOTAL

Firstly, 85% = 85/100 = 0.85

Remember, is means =

of means multiplication

So we have:

8219.5 = 0.85 * Total

Hence, total = [let total be 7]

8219.5 = 0.85 * t

t = 8219.5/0.85 = 9670 feet

4 0

3 years ago

What is the measure of angle c?

svlad2 [7]

Answer:

c=29°

Step-by-step explanation:

angle b=97°{ vertically opposite angle}

now,

97°+54°+c=180°{ sum of angle of triangle}

x=180-151
x=29°

<h2>stay safe healthy and happy.</h2>

4 0

3 years ago

Read 2 more answers

Expression equivelent to 2/5 divided by 6

Oksanka [162]

Answer:

1/15

Step-by-step explanation:

(2/5)/6 = 2/(5*6) = 2/30 = 1/15

8 0

3 years ago

You are allowed to go to the store and spend your allowance on one of these three items: ball, candy, or hat. Which one would yo

11Alexandr11 [23.1K]

I would choose a hat, because it is stylish and can keep me warm. My opportunity cost would be a ball, because it is useful for boring, lonely days. This is what I would write, Idk if you like it or not.

3 0

3 years ago

Read 2 more answers

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago